Question

我正在编写一个JAX-RS Web服务，它将JSON返回给客户端，我正在尝试使用org.codehaus.jackson库来处理JSON对象。我遇到的问题是我的JsonNode在返回客户端之前没有正确序列化。响应中有许多无关的属性。我希望返回JsonNode最简单的JSON表示。

这是一个（人为的）例子：

@GET
@Path("user")
@Produces(MediaType.APPLICATION_JSON)
public JsonNode getUser() {
    ObjectNode node = JsonNodeFactory.instance.objectNode();
    node.put("user", "jDoe");
    return node;
}

JSON对此的回应非常难看：

{"object":true,"elements":[{"textual":true,"textValue":"jDoe","binaryValue":"jDoe","valueAsText":"jDoe","valueNode":true,"containerNode":false,"missingNode":false,"array":false,"object":false,"pojo":false,"number":false,"integralNumber":false,"floatingPointNumber":false,"int":false,"long":false,"double":false,"bigDecimal":false,"bigInteger":false,"boolean":false,"null":false,"binary":false,"booleanValue":false,"intValue":0,"longValue":0,"doubleValue":0.0,"decimalValue":0,"bigIntegerValue":0,"valueAsInt":0,"valueAsLong":0,"valueAsDouble":0.0,"valueAsBoolean":false,"elements":[],"fieldNames":[],"fields":[]}],"fieldNames":["user"],"fields":[{"key":"user","value":{"textual":true,"textValue":"jDoe","binaryValue":"jDoe","valueAsText":"jDoe","valueNode":true,"containerNode":false,"missingNode":false,"array":false,"object":false,"pojo":false,"number":false,"integralNumber":false,"floatingPointNumber":false,"int":false,"long":false,"double":false,"bigDecimal":false,"bigInteger":false,"boolean":false,"null":false,"binary":false,"booleanValue":false,"intValue":0,"longValue":0,"doubleValue":0.0,"decimalValue":0,"bigIntegerValue":0,"valueAsInt":0,"valueAsLong":0,"valueAsDouble":0.0,"valueAsBoolean":false,"elements":[],"fieldNames":[],"fields":[]}}],"containerNode":true,"valueNode":false,"missingNode":false,"array":false,"pojo":false,"number":false,"integralNumber":false,"floatingPointNumber":false,"int":false,"long":false,"double":false,"bigDecimal":false,"bigInteger":false,"textual":false,"boolean":false,"null":false,"binary":false,"booleanValue":false,"intValue":0,"longValue":0,"doubleValue":0.0,"decimalValue":0,"bigIntegerValue":0,"valueAsInt":0,"valueAsLong":0,"valueAsDouble":0.0,"valueAsBoolean":false}

我希望它只是

{"user":"jDoe"}

我错过了什么吗？我不明白为什么将一个简单的JsonNode序列化为JSON会出现问题。

对于它的价值，从JSON4J库返回JSONObject按预期工作，但我更喜欢使用Jackson的库。

Answer 1

这应该按原样运行，所以我怀疑可能存在版本不兼容。由于Jersey使用Jackson 1.x（1.8或1.9），你需要使用相同的版本; 2.0类在不同的Java包中，允许1.x和2.x共存（以避免强制升级）。

因此，请确保您使用的是与泽西相同的版本。

杰克逊的JsonNode与JAX-RS

1 个答案: