我正在尝试过滤和排序包含聊天消息列表的NSMutableArray。我正在尝试获取2个用户之间的对话的最后消息。例如,如果user1与2个不同的用户有2个不同的对话,我想获得每个对话的最后一条消息。我正在使用Parse.com作为后端,这就是我如何保存&检索邮件。
保存邮件
PFUser *user = [[PFUser currentUser] objectForKey:@"displayName"];
PFObject *newMessage = [PFObject objectWithClassName:@"Messages"];
[newMessage setObject:messageStr forKey:@"body"];
[newMessage setObject:self.mySelectedUser forKey:@"toUser"];
[newMessage setObject:user forKey:@"fromUser"];
[newMessage saveInBackground];
myMessageField.text = @"";
[self getTheNewMessages];
[self.myTView reloadData];
检索讯息
-(void)GetmyNewMessages
{
PFQuery *query1 = [PFQuery queryWithClassName:@"Messages"];
[query1 whereKey:@"toUser" equalTo:[[PFUser currentUser] objectForKey:@"displayName"]];
[query1 whereKeyExists:@"date"];
PFQuery *query2 = [PFQuery queryWithClassName:@"Messages"];
[query2 whereKey:@"fromUser" equalTo:[[PFUser currentUser] objectForKey:@"displayName"]];
[query2 whereKeyExists:@"date"];
PFQuery *query = [PFQuery orQueryWithSubqueries:[NSArray arrayWithObjects:query1, query2, nil]];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
if (!error) {
NSLog(@"Successfully retrieved %d chats.", objects.count);
[premessagesList removeAllObjects];
[premessagesList addObject:objects];
} else {
//Log details of the failure
NSLog(@"Error: %@ %@", error, [error userInfo]);
}
}];
}
NSMutableArray的NSLog(premessageList)
( "<Messages:aS8tVIlsHc:(null)> {\n
body = hi;\n fromUser = cnn;\n toUser =FNC;\n
date = \"2012-09-19 02:40:29 +0000\";\n}",
"<Messages:CPCa6VBmf7:(null)> {\n
body = hello;\n fromUser = FNC;\n toUser =cnn;\n
date = \"2012-09-20 05:06:05 +0000\";\n}",
"<Messages:Jz1cILt18Y:(null)> {\n
body = whatsgood;\n fromUser = sleepy;\n toUser =cnn;\n
date =\"2012-09-20 05:06:05 +0000\";\n}",
"<Messages:lXretmE1uK:(null)> {\n
body = lol;\n fromUser = cnn;\n toUser =sleepy;\n
date =\"2012-09-20 05:13:16 +0000\";\n}",
我尝试使用NSSortDescriptor和NSPredicate,但我得到了一个空的tableview。
答案 0 :(得分:0)
在这类问题中,我会使用一些变量和快速迭代来浏览信息并得到你需要的东西:
id lastChat = ni;
... temps
for(OneChat in allChats) {
do tests and set variables
}
Now I know the last chat.
PS:我决定不发布这个,但是当我看到很长一段时间没有人回应后觉得它总比没有好。这就是我解决这个问题的方法。
答案 1 :(得分:0)
您可以限制结果并按照PFQuery
本身进行排序:
[query1 orderByDescending:@"createdAt"];
query1.limit = 1;
[query2 orderByDescending:@"createdAt"];
query2.limit = 1;