我只是学习了如何使用ListView并在此tutorial之后解析Java中的XML数据。但是,我收到一个错误,因为XML数据包含一些特殊字符。有人可以就这个问题向我提出建议吗?
这是我的XML数据。
<menu>
<item>
<id>1</id>
<question>What's my phone number?</question>
<answer>my phone number is "000-000-0000".</answer>
</item>
<item>
<id>2</id>
<question>What's my fax number?</question>
<answer>my fax number is "000-000-0000"</answer>
</item>
<item>
<id>3</id>
<question>What's my mailing address?</question>
<answer>my address here</answer>
</item>
<item>
<id>4</id>
<question>What's my web address?</question>
<answer>https://mywebsite.com/Login/Login.aspx?cID=53044&lng=en-US</answer>
</item>
</menu>
这是Java类。
public class FaqsQuestionsActivity extends ListActivity {
static final String URL = "http://myweb.com/faq_list.xml";
// XML node keys
static final String KEY_ITEM = "item"; // parent node
static final String KEY_ID = "id";
static final String KEY_QUESTION = "question";
static final String KEY_ANSWER = "answer";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.faqs_questions);
ArrayList<HashMap<String, String>> menuItems = new ArrayList<HashMap<String, String>>();
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(URL); // getting XML
Document doc = parser.getDomElement(xml); // getting DOM element
NodeList nl = doc.getElementsByTagName(KEY_ITEM);
for (int i = 0; i < nl.getLength(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element) nl.item(i);
map.put(KEY_ID, parser.getValue(e, KEY_ID));
map.put(KEY_QUESTION, parser.getValue(e, KEY_QUESTION ));
map.put(KEY_ANSWER, parser.getValue(e, KEY_ANSWER));
menuItems.add(map);
}
ListAdapter adapter = new SimpleAdapter(this, menuItems, R.layout.faqs_question_list,
new String[] { KEY_QUESTION, KEY_ANSWER }, new int[] {R.id.question, R.id.answer});
setListAdapter(adapter);
ListView lv = getListView();
lv.setOnItemClickListener(new OnItemClickListener() {
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
String question = ((TextView) view.findViewById(R.id.question)).getText().toString();
String answer = ((TextView) view.findViewById(R.id.answer)).getText().toString();
Intent in = new Intent(getApplicationContext(), FaqsAnswersActivity.class);
in.putExtra(KEY_QUESTION, question);
in.putExtra(KEY_ANSWER, answer);
startActivity(in);
}
});
}
}
答案 0 :(得分:0)
在尝试解析XML之前,您可以尝试对XML进行编码:
String encodedXML = URLEncoder.encode(xml);
然后解析。