我有一个日期格式: 2009-08-10T16:03:03Z
我要转换为: @“MMM dd,HH:mm a”
我在NSString中检索xml格式。我试图使用NSDateformatter: NSDateFormatter * df = [[NSDateFormatter alloc] init]; [df setDateFormat:@“MMM dd,HH:mm a”];
任何想法?
答案 0 :(得分:6)
NSString *yourXMLDate = @"2009-08-10T16:03:03Z"
NSDateFormatter *inputFormatter = [[NSDateFormatter alloc] init];
[inputFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss"];
NSDate *inputDate = [inputFormatter dateFromString:yourXMLDate];
NSDateFormatter *outputFormatter = [[NSDateFormatter alloc] init];
[outputFormatter setDateFormat:@"MMM dd, HH:mm a"];
NSString *outputDate = [outputFormatter stringFromDate:inputDate];
希望这有帮助!
答案 1 :(得分:2)
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setDateFormat:@"E, d LLL yyyy HH:mm:ss Z"]; // Thu, 18 Jun 2010 04:48:09 -0700
NSDate *date = [dateFormatter dateFromString:self.currentDate];
[item setObject:date forKey:@"date"];
[items addObject:[item copy]];
此处编辑以下代码
[dateFormatter setDateFormat:@"E, d LLL yyyy HH:mm:ss Z"]; // Thu, 18 Jun 2010 04:48:09 -0700
到您所需的格式。