我有一个包含Identity,RecordId,Type,Reading和IsDeleted列的表。标识是自动递增的主键,RecordId是可以具有重复值的整数,类型是可以是“一”或“平均”的读取类型,读取是包含任何整数值的整数,IsDeleted是位可以是0或1,即假或真。 现在,我希望查询包含表的所有记录,如果每个RecordId的COUNT(Id)大于2,则显示该RecordId的所有记录。
如果该特定RecordId的COUNT(Id)== 2且两者的读数值即“一”或“平均”类型的记录相同,则仅显示平均记录。
如果COUNT(Id)== 1,则只显示该记录。
例如:
Id RecordId Type Reading IsDeleted
1 1 one 4 0
2 1 one 5 0
3 1 one 6 0
4 1 average 5 0
5 2 one 1 0
6 2 one 3 0
7 2 average 2 0
8 3 one 2 0
9 3 average 2 0
10 4 one 5 0
11 4 average 6 0
12 5 one 7 0
Ans结果可以是
Id RecordId Type Reading IsDeleted
1 1 one 4 0
2 1 one 5 0
3 1 one 6 0
4 1 average 5 0
5 2 one 1 0
6 2 one 3 0
7 2 average 2 0
9 3 average 2 0
10 4 one 5 0
11 4 average 6 0
12 5 one 7 0
简而言之,我想跳过'one'类型的读数,它的平均读数具有相同的值,并且“一”类型读数的计数不超过一个。
答案 0 :(得分:2)
查看此计划
DECLARE @t TABLE(ID INT IDENTITY,RecordId INT,[Type] VARCHAR(10),Reading INT,IsDeleted BIT)
INSERT INTO @t VALUES
(1,'one',4,0),(1,'one',5,0),(1,'one',6,0),(1,'average',5,0),(2,'one',1,0),(2,'one',3,0),
(2,'average',2,0),(3,'one',2,0),(3,'average',2,0),(4,'one',5,0),(4,'average',6,0),(5,'one',7,0),
(6,'average',6,0),(6,'average',6,0),(7,'one',6,0),(7,'one',6,0)
--SELECT * FROM @t
;WITH GetAllRecordsCount AS
(
SELECT *,Cnt = COUNT(RecordId) OVER(PARTITION BY RecordId ORDER BY RecordId)
FROM @t
)
-- Condition 1 : When COUNT(RecordId) for each RecordId is greater than 2
-- then display all the records of that RecordId.
, GetRecordsWithCountMoreThan2 AS
(
SELECT * FROM GetAllRecordsCount WHERE Cnt > 2
)
-- Get all records where count = 2
, GetRecordsWithCountEquals2 AS
(
SELECT * FROM GetAllRecordsCount WHERE Cnt = 2
)
-- Condition 3 : When COUNT(RecordId) == 1 then display only that record.
, GetRecordsWithCountEquals1 AS
(
SELECT * FROM GetAllRecordsCount WHERE Cnt = 1
)
-- Condition 1: When COUNT(RecordId) > 2
SELECT * FROM GetRecordsWithCountMoreThan2 UNION ALL
-- Condition 2 : When COUNT(RecordId) == 2 for that specific RecordId and Reading value of
-- both i.e. 'one' or 'average' type of the records are same then display only
-- average record.
SELECT t1.* FROM GetRecordsWithCountEquals2 t1
JOIN (Select RecordId From GetRecordsWithCountEquals2 Where [Type] = ('one') )X
ON t1.RecordId = X.RecordId
AND t1.Type = 'average' UNION ALL
-- Condition 2: When COUNT(RecordId) = 1
SELECT * FROM GetRecordsWithCountEquals1
<强>结果强>
ID RecordId Type Reading IsDeleted Cnt
1 1 one 4 0 4
2 1 one 5 0 4
3 1 one 6 0 4
4 1 average5 0 4
5 2 one 1 0 3
6 2 one 3 0 3
7 2 average2 0 3
9 3 average2 0 2
11 4 average6 0 2
12 5 one 7 0 1
答案 1 :(得分:1)
假设您的表名为the_table
,请执行以下操作:
select main.*
from the_table as main
inner join (
select recordId, count(Id) as num, count(distinct Reading) as reading_num
from the_table
group by recordId
) as counter on counter.recordId=main.recordId
where num=1 or num>2 or reading_num=2 or main.type='average';
未经测试,但应该是其中的一些变体。
简短摘要是我们想要使用o =本身的聚合版本加入表格,然后根据您提到的计数条件对其进行过滤(num = 1,然后显示它; num = 2,仅显示平均记录如果读数相同则显示两者; num> 2,显示所有记录。
答案 2 :(得分:1)
;with a as
(
select Id,RecordId,Type,Reading,IsDeleted, count(*) over (partition by RecordId, Reading) cnt,
row_number() over (partition by RecordId, Reading order by Type, RecordId) rn
from table
)
select Id,RecordId,Type,Reading,IsDeleted
from a where cnt <> 2 or rn = 1