Question

实际上我试图在没有链接到db的情况下创建搜索功能。所以我只是把它放在模特身上。现在我不知道如何在控制器中调用该数据。希望任何人都能解决我的问题。

这是我的观点页面：

<li>Category:
<div>
<? echo form_dropdown('fcategory', $content_category); ?> </div></li>

<li> Channel:<div>
<? echo form_dropdown('fchannel', $content_channel); ?></div> </li>

<li> Language<div>
<? echo form_dropdown('flanguage', $content_language); ?></div> </li>

<input type="submit" class="btn" name="search" value="Search" /> <span class="lightfont"></span>

这是我的模特：

function general(){

    $data['content_category'] = array(
        "Dramas"=>"Dramas",
        "Movies"=>"Movies",
        "News"=>"News",
        "Anime"=>"Anime",
        "Popular Selection"=>"Popular Selection"
    );

    $data['content_channel'] = array(
        "China"=>"China",
        "Hong Kong"=>"Hong Kong",
        "Taiwan"=>"Taiwan",
        "Japan"=>"Japan",
        "Korea"=>"Korea",
        "UK"=>"UK",
        "US"=>"US",
        "Indonesia"=>"Indonesia"
    );


    $data['content_language'] = array(
        "English"=>"English",
        "Chinese"=>"Chinese",
        "Others"=>"Others"
    );

    return $data;
}


function sample_data(){

    $TVContent ['China']['Chinese']['Movies'][1]= array ('title'=>'Gooddrama','home-index-china movies', 'English', 'Grey');
    $TVContent ['China']['Chinese']['Drama'][2]= array ('title'=>'Gooddrama','home-index-china drama', 'English', 'Grey');
    $TVContent ['China']['English']['Sport'][3]= array ('title'=>'ABO','', 'English', 'Grey');
    $TVContent ['China']['Chinese']['News'][4]= array ('title'=>'KTD','', 'Chinese', 'Grey');

    $TVContent ['China']['Chinese']['Movies'][1]['title'];
}

Answer 1

使用数据库存储数据将是最佳实现

这是如何从控制器调用模型功能

//加载模型

$这 - ＆GT;负载＆GT;模型（ 'product_model'）;

//调用模型函数

$这 - ＆GT; product_model-＆GT; your_function（）;

欲了解更多信息， http://codeigniter.com/user_guide/general/models.html

如何创建没有链接数据库的搜索功能

1 个答案: