传递_id的参数并更新SQLitedatabase

时间:2012-09-25 03:54:33

标签: android sqlite android-listview

我正在尝试使用行id作为我的where语句来更新SQLite表。我从列表视图中显示的行中获取行_id并使用此语句传递给另一个活动:

Cursor cursor = (Cursor) nurseTableAdapter.getItem((int)id);
            showAssignments.putExtra("Nurse", cursor.getInt(cursor.getColumnIndex("_id")));

接收活动接收参数:

nurse = extras.getString("Nurse");

并将其作为参数传递给我的DbCommunicator类:

updateAssignments.updateNurseAssignments(listItemsArray, nurse);

我的DbCommunicator类用它做了这个:

public void updateNurseAssignments(String[] choices, String nurseId) {
    // set parameter variables
    //int nurseIdToInt = Integer.parseInt(nurseId);
    //String strFilter = "_id=" + nurseIdToInt;
    //String where = "_id=?";
    String[] whereArgs = {String.valueOf(nurseId)};
    Log.i(TAG, "value of whereArgs is " + whereArgs[0]);

    // set content values
    ContentValues cvUpdate = new ContentValues();
    cvUpdate.put(KEY_FIRST_ASSIGNMENT, choices[0]);
    cvUpdate.put(KEY_SECOND_ASSIGNMENT, choices[1]);
    cvUpdate.put(KEY_THIRD_ASSIGNMENT, choices[2]);
    cvUpdate.put(KEY_FOURTH_ASSIGNMENT, choices[3]);
    cvUpdate.put(KEY_FIFTH_ASSIGNMENT, choices[4]);
    cvUpdate.put(KEY_SIXTH_ASSIGNMENT,  choices[5]);

    // update database
    sqldb.update(NURSE_TABLE, cvUpdate, KEY_NURSE_ROWID + "= ?", whereArgs); 
}

我没有收到任何错误,但表格没有更新。我在Stack Overflow中只找到了一个类似的例子,并试图在这里加入一些,但仍然有问题。建议表示赞赏。

0 个答案:

没有答案