Question

我正在Oracle中练习一些例子，因为我是新手。我想显示在下面的表的最后和最后匹配的WHERE子句行的First WHERE子句匹配的行。

  CREATE table demo(id int, name varchar(50), city varchar(20), zip varchar(20));
    insert into demo values(1,'oliver71','munich','85716');

    insert into demo values(2,'markus71','munich','85716');
    insert into demo values(3,'oliver81','stuttgart','70024');
    insert into demo values(4,'peter82','hale','81978');
    insert into demo values(5,'chinnarose71','rosenheim','80324');
    insert into demo values(6,'guru11','berlin','81982');
    insert into demo values(7,'sachin51','frankfurt','00712');

    select name, city, zip from demo where zip like '%7%' OR city LIKE '%7%' 
     OR name LIKE '%7%';

我如何在Oracle中做到这一点。任何建议将不胜感激。

Answer 1

您的查询中没有“WHEN”子句。我假设你的意思是WHERE子句的部分。

为此，您需要一种排序结果的方法。这是使用子查询的一种方法，我认为这可能是最清楚的：

select name, city, zip
from (select name, city, zip,
             (case when zip like '%7%' then 1
                   when city LIKE '%7%' then 2
                   when name LIKE '%7%' then 3
                   else 0
              end) as matchitem
      from demo
     ) d
where matchitem > 0
order by matchitem

如何显示Oracle搜索结果？

1 个答案: