Question

我在Symfony 2.1项目中安装了KnpPaginatorBundle，并配置了Paginator。

使用分页我的网址如下：

http://dev.localhost/app_dev.php/news/development?page=3

是否可以将URL更改为此类（或类似的 - 没有？和=字符）？

http://dev.localhost/app_dev.php/news/development/page/3

Answer 1

我找到解决方案，解决您的问题，请按照以下步骤操作：

1）创建新路由或更改旧路由，因此在routing.yml中添加以下内容：

news_development_route:
    pattern: /news/development/{page}
    defaults: {_controller: AcmeMainBundle:Article:list, page: 1 }

2）在你的类控制器中，改变你的方法：

// Acme\MainBundle\Controller\ArticleController.php

public function listAction($page)/*add the $page param*/
{
    $em    = $this->get('doctrine.orm.entity_manager');
    $dql   = "SELECT a FROM AcmeMainBundle:Article a";
    $query = $em->createQuery($dql);

    $paginator  = $this->get('knp_paginator');
    $pagination = $paginator->paginate(
        $query,
        $this->get('request')->query->get('page', $page)/*change the number 1 by the $page parameter*/,
        10/*limit per page*/
    );
    $pagination->setUsedRoute('news_development_route'); /*define the pagination route*/

    // parameters to template
    return $this->render('AcmeMainBundle:Article:list.html.twig', array('pagination' => $pagination));
}

就是这样

Answer 2

在你的控制器中，你需要改变它：

/**
 * @Route("/list/", name="_user_list")
 * @Template()
 */
public function listAction()
{
    $em = $this->get('doctrine.orm.entity_manager');
    $dql = "SELECT a FROM HPPTarjetaBundle:User a";
    $query = $em->createQuery($dql);

    $paginator = $this->get('knp_paginator');
    $pagination = $paginator->paginate(
        $query,
        $this->get('request')->query->get('page', 1)/*page number*/,
        10/*limit per page*/
    );
    return compact('pagination');
}

...对此（参见“page”参数）：

/**
 * @Route("/list/{page}", name="_user_list")
 * @Template()
 */
public function listAction($page)
{
    $em = $this->get('doctrine.orm.entity_manager');
    $dql = "SELECT a FROM HPPTarjetaBundle:User a";
    $query = $em->createQuery($dql);

    $paginator = $this->get('knp_paginator');
    $pagination = $paginator->paginate(
        $query,
        $page/*page number*/,
        10/*limit per page*/
    );
    return compact('pagination');
}

如何使用KnpPaginatorBundle的友好URL

2 个答案: