Question

如果我的数组结构如下：

[0] => bad
[1] => good
[2] => bad
[3] => bad
[4] => good
[5] => bad
[6] => bad
[7] => good
[8] => bad
[9] => bad
[10] => good
[11] => bad

我需要一个只包含好项目的数组：

[0] => good
[1] => good
[2] => good
[3] => good
[4] => good

我该怎么办？

Answer 1

您可以使用array_filter功能：

$good_value ="good";
$new_array = array_filter($old_array,function($value)use($good_value){
                                 return $value === $good_value;
                                });

Answer 2

您还可以使用利用foreach和array_push的方法：

$goodArray = array();
foreach($array as $value) {
    if $value = "good" {
        array_push($goodArray, $value);
    }
}

或者如果您想保留原始索引：

$goodArray = array();
foreach($array as $key => $value) {
    if ($value = "good") {
        $goodArray[$key] = $value;
    }
}

Answer 3

你可以使用一个循环

$newArray = array();
foreach($oldArray as $value) {
  if($value == 'good')
    $newArray[] = $value
}

如果您需要保留密钥

$newArray = array();
foreach($oldArray as $key=>$value) {
  if($value == 'good')
    $newArray[$key] = $value
}

Answer 4

使用PHP的array_filter()函数。

function good($var)
{
    return($var == "good");
}
$ary = array_filter($ary, "good");
print_r($ary);

如果需要重新索引数组，只需添加：

$ary = array_values($ary);

<强> CodePad example

从数组中提取所需的项目

4 个答案: