Android Socket被绞死

时间:2012-09-24 06:39:18

标签: android sockets

我已经创建了一个服务,而这又创建了一个Socket,但是一旦尝试读取从Server发送的数据,它就会挂起,另一方面,如果我没有使用Service但是普通的Activity会运行相同的代码? / p>

        import android.app.*;
        import android.content.*;
        import android.os.*;
        import android.util.*;
        import java.net.*;
        import java.io.*;
        import android.widget.*;




     public class BackgroundService extends Service
            {
                    private Socket socket=null;
                    private  InputStreamReader  in=null;
                    private String ip;

                    private String tag="BackgroundService";

                    public IBinder onBind(Intent p1)
                    {
                            // TODO: Implement this method
                            return null;
                    }

             public void onCreate(){
                     super.onCreate();




             }
            public void onStart(Intent i,int id){
             super.onStart(i,id);
                    ip=i.getStringExtra("Ip");

             Log.v(tag,"Ip "+i.getStringExtra("Ip"));
                    try
                    {
                            socket = new Socket(ip.trim(), 8888);
                            new Runnable() {

                                    public void run()
                                    { 
//                                        Hangs in this block.....
                                            try
                                            {
                                                    in = new InputStreamReader (socket.getInputStream());
                                            BufferedReader bf=new BufferedReader (in);
        //                                 Never Reaches this messge
                                            Log.v(tag,"mess:"+bf.readLine() );
                                            }
                                            catch (IOException e)
                                            {
                                                    e.printStackTrace();
                                            }


                                    }


                            }.run();



                    }
                    catch (IOException e)
                    {
                            e.printStackTrace();
                    }



            }

            }

1 个答案:

答案 0 :(得分:2)

Log.v是它不允许你打印值的问题所以使用System.out.println()和bf.printline将包含消息