如何将mysql查询转换为yii。?
我有3张桌子
这是我的SQL查询
SELECT t.email
FROM otz_user_header t
JOIN otz_customers r
ON t.user_id = r.customer_user_id
JOIN otz_customer_ratings cr
ON cr.customer_user_id = r.customer_user_id
WHERE r.rate_auto_approve = 0
AND r.rate_email_time IS NOT NULL
AND r.total_rating_count IS NOT NULL
AND cr.rating_date < Curdate()
AND cr.rating_date > Date_sub(Curdate(), INTERVAL 7 day)
如何将此查询转换为yii?
提前致谢。
答案 0 :(得分:10)
&#34;鼬&#34;回答是正确的,但如果你正在寻找积极的记录......
型号: UserHeader
关系:
'activeCustomers' => array(
self::HAS_MANY,
'Customer',
'customer_user_id',
'condition' => 'activeCustomers.rate_auto_approve=0
AND activeCustomers.rate_email_time IS NOT NULL
AND activeCustomers.total_rating_count IS NOT NULL'
),
型号:客户
关系:'lastWeekRatings' => array(
self::HAS_MANY,
'CustomerRating',
'customer_user_id',
'condition' => 'lastWeekRatings.rating_date < CURDATE()
AND lastWeekRatings.rating_date > DATE_SUB( CURDATE(), INTERVAL 7 DAY )'
),
以下代码返回与查询相同的MODEL对象。 (我还没有测试过它)
$useremails = UserHeader::model()
->with('activeCustomers', 'activeCustomers.lastWeekRatings')
->findAll(array(
'select' => 't.email'
));
print_r($useremails);
答案 1 :(得分:5)
使用DAO(数据访问对象)
<强> MODEL 强>
public function test(){
$sql = "SELECT t.email
FROM otz_user_header t
JOIN otz_customers r ON t.user_id = r.customer_user_id
JOIN otz_customer_ratings cr ON cr.customer_user_id = r.customer_user_id
WHERE r.rate_auto_approve =0
AND r.rate_email_time IS NOT NULL
AND r.total_rating_count IS NOT NULL
AND cr.rating_date < CURDATE( )
AND cr.rating_date >DATE_SUB( CURDATE( ) , INTERVAL 7
DAY )";
return Yii::app()->db->createCommand($sql)->queryAll();
}