如何在SQL表中选择2个数据？

Question

我有2张这样的表：

Table 1
-------
ID
score

Table 2
-------
ID
score_from
score_to

如果我根据表2中的score_from和score_to在表1中得分='12'，我如何从表2中获取ID？

Contents of Table1:
----------------------
ID          |Score   |
----------------------
1           |12      |
----------------------
2           |40      |
----------------------

Contents of Table2:
------------------------------
ID       |score_from|score_to|
------------------------------
1        |0         |20      |
------------------------------
2        |21        |40      |
------------------------------

如果我从table1获得得分='12'，我如何编写查询以获得表2中的ID ='1'？

Answer 1

试试这个，

SELECT a.`ID`, a.`Score`, b.`ID`, b.`score_from`, b.`score_to`
FROM   table1 a, table2 b
WHERE  (a.score BETWEEN b.score_from AND b.score_to) AND
        (a.score = 12)

SQLFiddle Demo

或者如果您只想要ID

SELECT b.`ID`
FROM   table1 a, table2 b
WHERE  (a.score BETWEEN b.score_from AND b.score_to) AND
        (a.score = 12)

SQLFiddle Demo

Answer 2

select t2.id from table t1 ,table t2
where t1.score between t2.score_from and t2.score_to;