Doctrine从子查询中选择

时间:2012-09-23 16:50:39

标签: php mysql doctrine

我试图通过doctrine运行以下查询:

$sql = "SELECT league_id, sum(num_fans) AS total_fans FROM ("
."SELECT COUNT(*) as num_fans, t.id AS team_id, l.id AS league_id FROM fan_link fl "
."JOIN team t ON fl.team_id = t.id JOIN League l ON t.league_id = l.id GROUP BY fl.team_id"
.") a GROUP BY league_id LIMIT 0, 3";

$results = $this->em->createQuery($sql)->getScalarResult();

查询在PHPMyAdmin中运行正常,但是当我尝试在doctrine中运行它时出现此错误:

Doctrine\ORM\Query\QueryException [ 0 ]: 
[Semantical Error] line 0, col 51 near '(SELECT COUNT(*)': 
Error: Class '(' is not defined.

括号(是否是教条查询中的保留字符?我在其他地方的where子句中有子选择,但是from子句中的这个子句不想工作。我做错了什么?

更新:
我刚刚尝试使用查询构建器并得到了相同的错误。代码:

$qb = $this->em->createQueryBuilder();
$leagueQuery = $qb->select('league_id, sum(num_fans) AS total_fans')
    ->from("(SELECT count(*) as num_fans, t.id AS team_id, l.id AS league_id "
    ."FROM fan_link fl "
    ."JOIN team t ON fl.team_id = t.id "
    ."JOIN League l ON t.league_id = l.id GROUP BY fl.team_id)",
    'a')
    ->groupBy("league_id")
    ->orderBy("total_fans", "DESC")
    ->setMaxResults(3)
    ->getQuery();

$results = $leagueQuery->getArrayResult();

2 个答案:

答案 0 :(得分:1)

结束使用:

$sql = "SELECT league_id, sum(num_fans) AS total_fans FROM "
    ."(SELECT COUNT(*) as num_fans, t.id AS team_id, l.id AS league_id FROM fan_link fl "
    ."JOIN team t ON fl.team_id = t.id JOIN League l ON t.league_id = l.id GROUP BY fl.team_id"
    .") a GROUP BY league_id LIMIT 0, 3";
$q = $this->em->getConnection();
$league_results = $q->fetchAll($sql);

答案 1 :(得分:0)

在完成这项工作的同时花了好几个小时!

你可以用 createNativeQuery()

来做到这一点

以下是工作示例:

$rsm = new ResultSetMapping();
$rsm->addScalarResult('c1', 'c1');
$rsm->addScalarResult('b1', 'b1');

$qb = $manager->createNativeQuery("
SELECT SUM(RESULTS.totalHours) AS c1, SUM(RESULTS.totalDuration) AS b1
FROM
(
    SELECT S.totalHours, S.totalDuration
    FROM S
    INNER JOIN SV ON S.specificationId = SV.id
    LEFT JOIN SToTagRel ST ON S.id = ST.specificationId
    LEFT JOIN T ON ST.tagId = T.id
    GROUP BY S.id
) AS RESULTS
", $rsm);

$qb->getSingleResult();