您好我想在iOS中查看iPhone设备版本。
我的意思是,目前正在运行的设备是iPhone 4或iPhone 5。
我需要查看设备,是不是iPhone 5?
因为我的应用程序中有一些问题需要知道iPhone 5。
那我该怎么办?
答案 0 :(得分:9)
添加此代码:
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone){
if ([[UIScreen mainScreen] respondsToSelector: @selector(scale)]) {
CGSize result = [[UIScreen mainScreen] bounds].size;
CGFloat scale = [UIScreen mainScreen].scale;
result = CGSizeMake(result.width * scale, result.height * scale);
if(result.height == 960) {
NSLog(@"iPhone 4 Resolution");
resolution_number = 1;
}
if(result.height == 1136) {
NSLog(@"iPhone 5 Resolution");
}
}
else{
NSLog(@"Standard Resolution");
}
}
答案 1 :(得分:9)
将此宏添加到您的代码中:
#define HEIGHT_IPHONE_5 568
#define IS_IPHONE ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_5 ([[UIScreen mainScreen] bounds ].size.height == HEIGHT_IPHONE_5 )
然后随时检查..
if (IS_IPHONE_5) {
//Code for iPhone5
}else{
//Code for earlier version
}
答案 2 :(得分:5)
根据此question的答案,您可以确定您使用的是哪种型号 通过这个:
NSString *deviceModel = [UIDevice currentDevice].model;
结果可以是其中一个值:iPod touch,iPhone,iPad,iPhone模拟器,iPad模拟器
对于特定型号,您可以通过在UIDevice.h
类上创建类别来确定您使用的版本:
的UIDevice + Utilities.h
#import <UIKit/UIKit.h>
@interface UIDevice (Utilities)
- (CGFloat)deviceModelVersion;
@end
的UIDevice + Utilities.m
#import "UIDevice+Utilities.h"
#include <sys/types.h>
#include <sys/sysctl.h>
@implementation UIDevice (Utilities)
- (CGFloat)deviceModelVersion
{
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *machine = malloc(size);
sysctlbyname("hw.machine", machine, &size, NULL, 0);
NSString *platform = [NSString stringWithUTF8String:machine];
free(machine);
if ([platform rangeOfString:@"iPhone"].location != NSNotFound)
{
return [[[platform stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] stringByReplacingOccurrencesOfString:@"," withString:@"."] floatValue];
}
else if ([platform rangeOfString:@"iPad"].location != NSNotFound)
{
return [[[platform stringByReplacingOccurrencesOfString:@"iPad" withString:@""] stringByReplacingOccurrencesOfString:@"," withString:@"."] floatValue];
}
else if ([platform rangeOfString:@"iPod"].location != NSNotFound)
{
return [[[platform stringByReplacingOccurrencesOfString:@"iPod" withString:@""] stringByReplacingOccurrencesOfString:@"," withString:@"."] floatValue];
}
else if ([platform rangeOfString:@"i386"].location != NSNotFound || [platform rangeOfString:@"x86_64"].location != NSNotFound)
{
return -1.0; //Currently it is not possible (or maybe it is, but I do not know)
//which type of simulator device model version your app is running
//so I am returning -1.0 device model version for all simulators types
}
return 0.0;
}
@end
如何调用函数deviceModelVersion
的示例:
CGFloat deviceModelVersion = [UIDevice currentDevice].deviceModelVersion;
可能的结果可能是1.0,1.1,......,2.0,2.1,......,3.0,3.1,..,4.0,4.1,..,5.0,5.1 ......
要确定它是否为iPhone 5,您将拥有
deviceModel : "iPhone"
和
deviceModelVersion : >=5.0 and < 6.0
答案 3 :(得分:1)
我实际上找到了一个#define来实现这个技巧
#define IS_IPHONE_5 (fabs((double)[[UIScreen mainScreen] bounds].size.height - (double) 568) < DBL_EPSILON)
答案 4 :(得分:0)
#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_4 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 480.0f)
#define IS_IPHONE_5 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 568.0f)
#define IS_IPHONE_6 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0f)
#define IS_IPHONE_6PLUS (IS_IPHONE && [[UIScreen mainScreen] nativeScale] == 3.0f)
#define IS_IPHONE_6_PLUS (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0f)
#define IS_RETINA ([[UIScreen mainScreen] scale] == 2.0f)