我希望计算仓库中的项目并计算仓库中的可用空间,然后输出到具有Inshelf列的表并且是免费的,我想出了类似的东西。
SELECT COUNT(*) as Inshelf, free=10-Inshelf
FROM stock.stockproduct
WHERE StockNum = 1
AND checkOutData is NULL;
似乎它不起作用,是否有针对此类问题的任何简单解决方案?
答案 0 :(得分:3)
这不起作用 - 聚合函数的结果(例如count()
)在考虑完所有记录之后才可用。你需要使用子查询,在子查询中进行计数,在外部查询中进行减法。在不知道您的数据库架构的情况下,这充其量是猜测,但是......
SELECT InShelf, free - InShelf
FROM (
SELECT count(*) AS Inshelf, free
FROM stockproduct
WHERE StockNum = 1 AND checkOutData IS NULL
GROUP BY somefield
) AS a
答案 1 :(得分:0)
工作!!
SELECT InShelf, 10 - InShelf
FROM (
SELECT count(*) AS Inshelf, count(*) AS free
FROM stock.stockproduct
WHERE StockNum = 1 AND checkOutData IS NULL
) AS a;
感谢所有人,并因为愚蠢=。='
而骄傲