我有一个GridView,我正在填充ArrayAdapter的自定义子类。此适配器返回我自定义为可选择的按钮(请参阅Android ImageButton with a selected state?)。这个工作到目前为止,单击按钮选择它们(使用选择器 - 背景可见)。
问题是:我无法从一开始就将这些按钮设置为选定状态。当我第一次启动视图时,它们只是显示未选中状态。
我创建了一个简单的测试项目来说明问题:
package com.example.buttonselection;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.GridView;
public class MainActivity extends Activity {
public class SelectButtonAdapter extends ArrayAdapter<String> {
public SelectButtonAdapter(Context context) {
super(context, 0);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
String name = getItem(position);
View rowView = convertView;
if (rowView == null || !(rowView instanceof Button)) {
rowView = new Button(getContext());
((Button)rowView).setOnClickListener(new OnClickListener() {
public void onClick(View button) {
if (button.isSelected()){
button.setSelected(false);
} else {
button.setSelected(true);
}
}
});
}
Button button = (Button)rowView;
button.setText(name);
button.setBackgroundResource(R.drawable.button_selection);
button.setSelected(true); // this does not work
return button;
}
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
GridView grid = (GridView)findViewById(R.id.gridview);
SelectButtonAdapter adapter = new SelectButtonAdapter(this);
adapter.add("One");
adapter.add("Two");
adapter.add("Three");
grid.setAdapter(adapter);
}
}
因此,我甚至无法恢复使用onSaveInstanceState保存的按钮的状态。我该如何解决或解决这个问题?
我很感激任何帮助!
编辑:这是我的button_selection.xml,虽然这应该没问题,因为选择按钮以后工作正常。
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true">
<shape>
<solid android:color="@color/bet_button_pressed" />
<stroke
android:width="2dip"
android:color="@color/white" />
</shape>
</item>
<item android:state_selected="true">
<shape>
<solid android:color="@color/bet_button_selected" />
<stroke
android:width="2dip"
android:color="@color/white" />
</shape>
</item>
<item>
<shape>
<gradient
android:angle="90"
android:startColor="@color/bet_button_dark_green"
android:endColor="@color/bet_button_light_green"
android:centerX="0.5"
android:centerY="0.5" />
<stroke
android:width="2dip"
android:color="@color/white" />
</shape>
</item>
</selector>
答案 0 :(得分:1)
我找到了这个bug的解决方法。我只是存储外部天气按钮被选中并覆盖按钮的ondraw-method以在每次绘制时设置正确的状态。这有一个额外的好处,选择可以更容易持久。
这是解决方法(只是一个简单的概念证明,我的生产代码更复杂):
package com.example.buttonselection;
import java.util.HashSet;
import java.util.Set;
import android.app.Activity;
import android.content.Context;
import android.graphics.Canvas;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.GridView;
public class MainActivity extends Activity {
public class SelectButtonAdapter extends ArrayAdapter<String> {
public SelectButtonAdapter(Context context) {
super(context, 0);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
String name = getItem(position);
View rowView = convertView;
if (rowView == null || !(rowView instanceof Button)) {
rowView = new Button(getContext()) {
@Override
protected void onDraw(Canvas canvas) {
setSelected(selectedButtons.contains(getText()));
super.onDraw(canvas);
}
};
((Button)rowView).setOnClickListener(new OnClickListener() {
public void onClick(View button) {
String text = ((Button)button).getText().toString();
if(selectedButtons.contains(text)) {
selectedButtons.remove(text);
} else {
selectedButtons.add(text);
}
button.invalidate();
}
});
}
Button button = (Button)rowView;
button.setText(name);
button.setBackgroundResource(R.drawable.button_selection);
return button;
}
}
private Set<String> selectedButtons = new HashSet<String>();
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
GridView grid = (GridView)findViewById(R.id.gridview);
SelectButtonAdapter adapter = new SelectButtonAdapter(this);
adapter.add("One");
adapter.add("Two");
adapter.add("Three");
grid.setAdapter(adapter);
// this selects the first button from the start
selectedButtons.add("One");
}
}
旁注: 有人会认为,版本4.1 API不会包含这样明显的错误。浪费在这上面的时间令人沮丧,并没有激励为这个系统开发更多。
答案 1 :(得分:1)
我遇到同样的问题。作为一种解决方法,我使用runnable来设置要选择的视图。
适用于您的情况:
@Override
public View getView(int position, View convertView, ViewGroup parent) {
String name = getItem(position);
View rowView = convertView;
if (rowView == null || !(rowView instanceof Button)) {
rowView = new Button(getContext());
((Button)rowView).setOnClickListener(new OnClickListener() {
public void onClick(View button) {
if (button.isSelected()){
button.setSelected(false);
} else {
button.setSelected(true);
}
}
});
}
Button button = (Button)rowView;
button.setText(name);
button.setBackgroundResource(R.drawable.button_selection);
final Handler handler = new Handler();
handler.postDelayed(new Runnable() {
@Override
public void run() {
button.setSelected(true);
}
}, 50);
return button;
}
50只是我选择使用的随机数,您可以根据需要进行更改。
这个解决方法适合我,我个人更喜欢这个,而不是覆盖onDraw方法。
希望这有助于某人。