将Func传递给List.Find

Question

我有以下代码：

    [TestMethod]
    public void A_Player_Can_Be_Deleted_From_The_List()
    {                     
        Player player = playerList.Find(ByName("Davy",whatGoesHere?);
        playerList.Remove(player);

        playerList.Count.Should().Be(2);
    }

Func'ByName'定义为：

Func<string, Player, bool> ByName = (name, player) => player.Name == name;

我不知道如何传递第二个（播放器）参数。有可能吗？

Answer 1

player被提供给您传递给List.Find<T>的谓词，因此您只需将其传递给ByName：

Player player = playerList.Find(p => ByName("Davy", p));
playerList.Remove(player);

您可以使用List<T>.RemoveAll，而不是Find和Remove。

playerList.RemoveAll(p => ByName("Davy", p));

Answer 2

如果要在ByName方法中使用Find委托，则必须为列表中的每个元素执行该委托。例如：

string player = playerList.Find((playerElement) => ByName("Davy", playerElement));