Question

我有一点cunundrum。我有一个Jquery / Js函数，可以从DropDownList中选择项目。然后将其分配给变量，并将变量传递给另一个函数。我唯一的问题是，当我第一次这样做时，一切正常。当我第二次调用该函数时，变量保持不变，而不是重新分配。

ddlCaseFilesNew，ddlCaseFilesOld，是我的两个DropDownLists。

这是我的功能：

function getCaseFiles(canMoveExpenses) {
        //create Popup with content from div
        var newCaseDdl = null;
        var oldCaseDdl = null;
        $('#ddlFiles').dialog({
            autoOpen: true,
            height: 'auto',
            width: 'auto',
            modal: true,
            buttons: {
                "Ok": function () {
                    //assign new CaseFile and old CaseFile for stored proc.
                    //var newCaseDdl = "";

                    newCaseDdl = $("#ddlCaseFilesNew").val();
                    alert("newCaseDdl = " + newCaseDdl);
                    //                      newCaseDdlInt = newCaseDdl.options[newCaseDdl.selectedIndex].value;

                    //var oldCaseDdl = "";
                    oldCaseDdl = $("#ddlCaseFilesOld").val();
                    //                        oldCaseDdlInt = oldCaseDdl.options[oldCaseDdl.selectedIndex].value;
                    alert("oldCaseDdl" + oldCaseDdl);
                    if (newCaseDdl != -1 && oldCaseDdl != -1) {
                        moveCasefile(canMoveExpenses, newCaseDdl, oldCaseDdl);
                        $(this).dialog('close');
                    }
                    else {
                        showMessage("Error. Please Select a Value From The Lists.");
                    }
                    oldCaseDdl = $("#ddlCaseFilesOld").selectedIndex = -1;
                    newCaseDdl = $("#ddlCaseFilesNew").selectedIndex = -1;
                },
                Cancel: function () {
                    newCaseDdl = null;
                    oldCaseDdl = null;
                    $(this).dialog('close');
                }
            }
        });
    }

我对Js / JQuery有点新鲜

oldCaseDdl和newCaseDdl是需要chagne到DropDownList的选定索引的变量

Answer 1

弄清楚原因。我从来没有为DropDownList实现“selection_changed”。

Javascript不会重新分配变量第二次调用函数

1 个答案: