计算具有特定日期值的记录

Question

我想获取在特定日期输入的所有记录，例如今天：

ALTER PROCEDURE [dbo].[SP_GET_QUEUESINFO_BY_DATE]
    @date nvarchar = '2012-09-21'
AS
BEGIN
    declare @dateStart nvarchar(50) = @date + ' 00:00:00.0'
    declare @dateEnd nvarchar(50) = @date + ' 23:59:59.437';
    declare @returnData table (allQueue int,inQueue int,outQueue int)

    SELECT 'table1' as table_name, COUNT(*) 
    FROM   Queue as Counts

    UNION ALL

    SELECT 'table2' as table_name,COUNT(*) FROM Queue as Counts 
    WHERE   QueueDate BETWEEN @dateStart AND @dateEnd 
    AND     QueueNumIn != 0

END

已编辑： 我现在编辑了我的代码：

ALTER PROCEDURE [dbo].[SP_GET_QUEUESINFO_BY_DATE]
AS
BEGIN
    declare @date2 datetime
    set @date2= '2012-09-21'

    SELECT 'AllQueue' as table_name, COUNT(*) 
    FROM    Queue as sdfds

    UNION ALL

    SELECT 'InQueue' as table_name,COUNT(*) 
    FROM    Queue as sdfds 
    WHERE   QueueDate >=@date2 
    AND     QueueNumIn != 0

    UNION ALL

    SELECT 'OutQueue' as table_name, COUNT(*) FROM  Queue as sdfds 
    WHERE   QueueDate >=@date2 
    AND     QueueNumOut != 0

END

它返回三条记录：

一个问题是第二列没有名称。为什么？另外，我想只返回一个有三行的记录，而不是三个有两个字段的单独记录。

Answer 1

如果你只想要那些在特殊日期的人，那就不知道为什么要全部归还。

另外，最好不要在日期之间使用

ALTER PROCEDURE [dbo].[SP_GET_QUEUESINFO_BY_DATE]
@date datetime = '2012-09-21'
AS
BEGIN

select count(*) as 'AllQueue' ,
sum(case when QueueDate >=@date and QueueNumIn != 0 THEN 1 else 0 end) as 'InQueue',
sum(case when QueueDate >=@date and QueueNumOut != 0 THEN 1 else 0 end) as  'OutQueue'
from Queue
END

这应该有效。

这会给你类似的东西

Allqueue              inqueue,      outqueue
----------------------------------------------------
    11      |             8        |   10

Answer 2

您需要将varchar转换为datetime。我想你想把Counts别名分配给Count（*）

ALTER PROCEDURE [dbo].[SP_GET_QUEUESINFO_BY_DATE] 
@date nvarchar = '2012-09-21' 
AS 
BEGIN 
declare @dateStart DATETIME = CAST(@date AS DATETIME) 
declare @dateEnd DATETIME = DATEADD(hh,24,CAST(@date AS DATETIME))
declare @returnData table (allQueue int,inQueue int,outQueue int) 
select 'table1' as table_name,COUNT(*) as Counts  from QUEUE AS tb1 
union all 
select 'table2' as table_name,COUNT(*) as Counts from QUEUE AS tb2  where QueueDate >=  @dateStart  and QueueDate  < @dateEnd and QueueNumIn !=0 
END

Answer 3

此代码已经过工作，并且是ElVieejo编辑的代码

ALTER PROCEDURE [dbo].[SP_GET_QUEUESINFO_BY_DATE]
AS
BEGIN
declare @date2 datetime
set @date2= '2012-09-21'
select COUNT(QueueID) ,
sum(case when QueueNumIn != 0 THEN 1 else 0 end) as 'InQueue',
sum(case when QueueNumOut != 0 THEN 1 else 0 end) as  'OutQueue'
from Queue where QueueDate >= @date2
END