Question

截图解释了这一切。 http://i46.tinypic.com/f3hobl.png

使用当前配置， InvoiceSentDate 仅接受8位日期（MM-DD-YY）。我希望能够捕捉MM-DD-YYYY日期。我该怎么做？

作为比较，请查看发票2106-2112 vs 2116。

FURTHERMORE，让事情复杂化！有些记录在日期之后有文字。 http://i50.tinypic.com/2r5qa88.png

Answer 1

您可以在纯T-SQL中执行此操作。这是工作SqlFiddle。

在这里，我找到patindex的日期，然后找到第一个非数字。这为substring提供了单独提取日期所需的参数。如您所见，我添加了一些测试数据，涵盖了各种可能性，包括斜线和破折号日期分隔符。

-- Test data
declare @Demo table (
    RawData varchar(100) null
)
insert into @Demo select 'JS sent via Unifier on 08/29/2012'
insert into @Demo select 'i sent via email on 09/07/12'
insert into @Demo select 'i sent via Unifier on 01/04/12; resubmitting p...'
insert into @Demo select 'JS sent via Unifier on 08-29-2012; resubmitting p...'
insert into @Demo select '08-29-2012; resubmitting p...'
insert into @Demo select '08-29-12'
insert into @Demo select 'no date here'
insert into @Demo select null

-- Actual query
select *,
    -- If there's a date, display it
    case when StartChar > 0 then substring(RawData, StartChar, DateLen) else null end as DateString 
from (
    select *,
        -- Find the first date
        patindex('%[0-1][0-9][/-][0-3][0-9][/-][0-9][0-9]%', RawData) as StartChar,
        -- Find the first non-digit after that date
        patindex(
            '%[^0-9]%', 
            right(
                RawData + '_', -- This underscore adds at least one non-digit to find
                len(RawData) - patindex('%[0-1][0-9][/-][0-3][0-9][/-][0-9][0-9]%', RawData) - 6
            )
        ) + 7 as DateLen
    from @Demo
) as a

<强>更新

如果您只是在寻找两种可能的日期格式，只需检查它们就可以使查询更简单：

select *,
    -- If there's a date, display it
    case
        when StartChar1 > 0 then substring(RawData, StartChar1, 10)
        when StartChar2 > 0 then substring(RawData, StartChar2, 8)
        else null
    end as DateString 
from (
    select *,
        -- Find the first MM-DD-YYYY
        patindex('%[0-1][0-9][/-][0-3][0-9][/-][0-9][0-9][0-9][0-9]%', RawData) as StartChar1,
        -- Find the first MM-DD-YY
        patindex('%[0-1][0-9][/-][0-3][0-9][/-][0-9][0-9]%', RawData) as StartChar2
    from @Demo
) as a

Answer 2

CndiedCode链接中的示例非常接近您的需求。

与Regex匹配略有不同

N'＃39; ^ \ d {3} - \ d {2} - \ d {4} $＆＃39;
去 N'＃39; \ d {2} / \ d {2} / \ d {2,4}＆＃39;

下面的代码看起来不同，因为必须逃避\

    if (Regex.IsMatch("sent on 01/01/10; ex", "\\d{2}/\\d{2}/\\d{2,4}"))
    {
        System.Diagnostics.Debug.WriteLine(Regex.Match("sent on 01/01/10; ex", "\\d{2}/\\d{2}/\\d{2,4}"));
    }
    if (Regex.IsMatch("sent on 01/01/2012; ex", "\\d{2}/\\d{2}/\\d{2,4}"))
    {
        System.Diagnostics.Debug.WriteLine(Regex.Match("sent on 01/01/2012; ex", "\\d{2}/\\d{2}/\\d{2,4}"));
    }

从字母数字字段中提取6-8位数日期

2 个答案: