Question

我有一个搜索表单，人们可以选择公司的几种服务，表格如下：

商家 business_id，business_name

商家数据

普林斯＆amp; amp;儿子

2，Smith Ltd

3，布朗斯

服务 service_id，service_name

服务数据

1，抛丸清理

2，绘画

3蒸汽清洁

Business_service business_id，service_id

1,1

1,2

2,2

3 1

3 2

因此，如果用户选择搜索一个项目，例如Shot Blasting，那么sql将是：

Select * FROM business 
Inner Join business_service On business_service.business_id  = business.business_id  
Inner Join service On service.service_id  = business_service.service_id 
WHERE business_service.service_id = 1

哪个工作正常，但是如果用户搜索提供“Shot Blasting”和“Painting”的业务我希望他们看到business_id 1和3.我知道以下sql不会工作但我想我会显示我要去的地方。

Select * FROM business 
Inner Join business_service On business_service.business_id  = business.business_id  
Inner Join service On service.service_id  = business_service.service_id 
WHERE business_service.service_id = 1 And business_service.service_id = 2

我知道这很简单，但我似乎无法理解它。

Answer 1

使用OR而不是AND。使用AND表示返回bussines_service，其中service id同时为1和2。相反，您需要具有服务ID = 1或服务ID = 2

的行

Answer 2

您可以使用IN

Select * FROM business 
Inner Join business_service On business_service.business_id  = business.business_id  
Inner Join service On service.service_id  = business_service.service_id 
WHERE service.service_id IN (1, 3)

Answer 3

您可以使用in代替where，理想情况下，您应该为服务ID 1或2设置"OR"条件。你查询会像

 Select * FROM business 
Inner Join business_service On business_service.business_id  = business.business_id  
Inner Join service On service.service_id  = business_service.service_id 
WHERE business_service.service_id in (1,2)

链接表上的Mysql查询

3 个答案: