Question

这个sql给出了像

这样的错误

ORA-01733：此处不允许使用虚拟列。

没有GET_PROPERTY函数，SQL可以工作。怎么解决？

UPDATE (SELECT VALUE, GET_PROPERTY (ORG.ID, 'BenefOperationCode') AS OPERATION_CODE
      FROM ORGANIZATION ORG, PROPERTY P
     WHERE ORG.EXTERNALKEY = '111' AND P.ID = ORG.ID AND P.IDX = 4)
SET VALUE = 123, OPERATION_CODE = 234;

Answer 1

编辑：由于ORA-01776错误，以下更新将无效（感谢Vincent）。请参阅新方法的结尾。

您正在尝试更新功能结果。这是不可能的。我假设您正在尝试更新函数检索的基础值。为此，您需要将功能代码与组织和属性之间的连接组合在一起。

我们说GET_PROPERTY是：

CREATE OR REPLACE FUNCTION GET_PROPERTY
(
    objectID_in NUMBER,
    propertyName_in VARCHAR
)
AS
    v_returnValue VARCHAR(32);
BEGIN
    SELECT
        PropertyValue INTO v_returnValue 
    FROM
        PropertyTable
    WHERE
        ObjectID = objectID_in
    AND PropertyName = propertyName_in;

    RETURN v_returnValue;
END

您的更新将成为：

--This wouldn't have worked.

编辑：最好编写一个程序来完成它。

CREATE PROCEDURE UpdateMyTwoTables
(
    orgExternalKey_in in VARCHAR,
    propertyIdx_in in NUMBER,
    propertyName_in in VARCHAR,
    newValue_in in VARCHAR,
    newPropertyValue_in in VARCHAR
)
AS
BEGIN
    UPDATE
    (SELECT
        ORG.Value
    FROM
        ORGANIZATION ORG, 
        PROPERTY P
    WHERE 
        ORG.EXTERNALKEY = orgExternalKey_in 
        AND P.ID = ORG.ID AND 
        P.IDX = propertyIdx_in)
    SET
        Value = newValue_in;

    UPDATE
    (SELECT
        PropertyValue
    FROM
        PropertyTable,
        ORGANIZATION ORG,
        PROPERTY P
    WHERE
        PropertyTable.objectID = ORG.ID
    AND ORG.ID = P.ID
    AND ORG.EXTERNALKEY = orgExternalKey_in
    AND P.Idx = propertyIdx_in
    AND PropertyTable.PropertyName = propertyName_in)
    SET
        PropertyValue = newPropertyValue_in;


END;

ORA-01733 - 使用update语句中的函数进行更新时，此处不允许使用虚拟列

1 个答案: