我需要编写一个程序来读取stdin
及其所有子文件夹的文件夹路径,然后根据文件的扩展名打印出文件数。
将编译如下:
java Summary -r <path>
输出需要看起来像:
txt:
number of files: 5
combined size: 1202131
largest file: 729224
smallest file: 12323
pdf:
number of files: 2
etc...
有人可以帮我这个吗?我不确定如何处理它。
答案 0 :(得分:4)
你可以从这样的东西开始递归地读取文件
public void listFilesForFolder(final File folder) {
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isDirectory()) {
listFilesForFolder(fileEntry);
} else {
System.out.println(fileEntry.getName());
}
}
}
此代码来自@rich。
剩下的细节是你必须解决的问题。
您可以查看Read all files in a folder了解详情
答案 1 :(得分:0)
看看这个:List files from directories and sub directories in java including only partial file paths
您将获得目录下所有文件的列表,然后您可以使用file.length()
来获取大小。
答案 2 :(得分:0)
类似于此代码的内容(来自http://www.javapractices.com/topic/TopicAction.do?Id=68):
JDK 7中的:
import java.io.IOException;
import java.nio.file.FileVisitResult;
import java.nio.file.FileVisitor;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.nio.file.SimpleFileVisitor;
import java.nio.file.attribute.BasicFileAttributes;
/** Recursive listing with SimpleFileVisitor in JDK 7. */
public final class FileListingVisitor {
public static void main(String... aArgs) throws IOException{
String ROOT = "C:\\test";
FileVisitor<Path> fileProcessor = new ProcessFile();
Files.walkFileTree(Paths.get(ROOT), fileProcessor);
}
private static final class ProcessFile extends SimpleFileVisitor<Path> {
@Override public FileVisitResult visitFile(
Path aFile, BasicFileAttributes aAttrs
) throws IOException {
System.out.println("Processing file:" + aFile);
return FileVisitResult.CONTINUE;
}
@Override public FileVisitResult preVisitDirectory(
Path aDir, BasicFileAttributes aAttrs
) throws IOException {
System.out.println("Processing directory:" + aDir);
return FileVisitResult.CONTINUE;
}
}
}
年长:
import java.util.*;
import java.io.*;
/**
* Recursive file listing under a specified directory.
*
* @author javapractices.com
* @author Alex Wong
* @author anonymous user
*/
public final class FileListing {
/**
* Demonstrate use.
*
* @param aArgs - <tt>aArgs[0]</tt> is the full name of an existing
* directory that can be read.
*/
public static void main(String... aArgs) throws FileNotFoundException {
File startingDirectory= new File(aArgs[0]);
List<File> files = FileListing.getFileListing(startingDirectory);
//print out all file names, in the the order of File.compareTo()
for(File file : files ){
System.out.println(file);
}
}
/**
* Recursively walk a directory tree and return a List of all
* Files found; the List is sorted using File.compareTo().
*
* @param aStartingDir is a valid directory, which can be read.
*/
static public List<File> getFileListing(
File aStartingDir
) throws FileNotFoundException {
validateDirectory(aStartingDir);
List<File> result = getFileListingNoSort(aStartingDir);
Collections.sort(result);
return result;
}
// PRIVATE //
static private List<File> getFileListingNoSort(
File aStartingDir
) throws FileNotFoundException {
List<File> result = new ArrayList<File>();
File[] filesAndDirs = aStartingDir.listFiles();
List<File> filesDirs = Arrays.asList(filesAndDirs);
for(File file : filesDirs) {
result.add(file); //always add, even if directory
if ( ! file.isFile() ) {
//must be a directory
//recursive call!
List<File> deeperList = getFileListingNoSort(file);
result.addAll(deeperList);
}
}
return result;
}
/**
* Directory is valid if it exists, does not represent a file, and can be read.
*/
static private void validateDirectory (
File aDirectory
) throws FileNotFoundException {
if (aDirectory == null) {
throw new IllegalArgumentException("Directory should not be null.");
}
if (!aDirectory.exists()) {
throw new FileNotFoundException("Directory does not exist: " + aDirectory);
}
if (!aDirectory.isDirectory()) {
throw new IllegalArgumentException("Is not a directory: " + aDirectory);
}
if (!aDirectory.canRead()) {
throw new IllegalArgumentException("Directory cannot be read: " + aDirectory);
}
}
}
答案 3 :(得分:0)
请使用以下代码。
public static void listFiles(final File folder) {
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isFile() && fileEntry.getName().endsWith(".txt")) {
System.out.println(fileEntry.getName());
}
if (fileEntry.isFile() && fileEntry.getName().endsWith(".pdf")) {
System.out.println(fileEntry.getName());
}
else {
listFiles(fileEntry);
}
}
}
public static void main(String startingPath){
File folder = new File(startingPath);
listFiles(folder);
}