Question

我试图用变量的内容写一个文件，但是如果文件不存在则创建它：

到目前为止我得到了这个：

echo "$Logstring" >> $fileLog

我缺少什么，因为当文件不存在时会出错。 if条件是否必要？

Answer 1

使用“触摸”命令：

touch $fileLog echo "$Logstring" >> $fileLog

Answer 2

   #! /bin/bash
   VAR="something to put in a file"
   OUT=$1
   if [ ! -f "$OUT" ]; then
       mkdir -p "`dirname \"$OUT\"`" 2>/dev/null
   fi
   echo $VAR >> $OUT

   # the important step here is to make sure that the folder for the file exists
   # and create it if it does not. It will remain silent if the folder exists.

$ sh out hello/how/are/you/file.out
geee: ~/src/bash/moo
$ sh out hello/how/are/you/file.out
geee: ~/src/bash/moo
$ sh out another/file/lol.hmz
geee: ~/src/bash/moo
$ find . 
.
./out
./another
./another/file
./another/file/lol.hmz
./hello
./hello/how
./hello/how/are
./hello/how/are/you
./hello/how/are/you/file.out
geee: ~/src/bash/moo
$ cat ./hello/how/are/you/file.out
something to put in a file
something to put in a file
geee: ~/src/bash/moo
$ cat ./another/file/lol.hmz 
something to put in a file

如果文件夹在名称中有空格，则需要转义“for dirname”。

写一个文件，如果它存在则追加，否则在bash中创建

2 个答案: