正数表示0到12之间的正数

Question

我试过没有运气来搜索互联网上的正则表达式来检查：

• 积极的＃
• 0到12之间

我需要把它放在这个特定代码行的括号中

 Regex rxValidHeightInches = new Regex();

非常感谢任何帮助！

由于

Answer 1

这应该有效^(\d|(1[0-2]))$

var rxValidHeightInches = new Regex("^(\\d|(1[0-2]))$");

Answer 2

试试这个。

(?<!-)(\b((1[01])|[1-9])\b)

匹配1 - 9或10或11。始终排除负数。

<强>释

-Assert that it is impossible to match the regex below with the match ending at this position (negative lookbehind) «(?<!-)»
---Match the character “-” literally «-»
-Match the regular expression below and capture its match into backreference number 1 «(\b((1[01])|[1-9])\b)»
---Assert position at a word boundary «\b»
---Match the regular expression below and capture its match into backreference number 2 «((1[01])|[1-9])»
------Match either the regular expression below (attempting the next alternative only if this one fails) «(1[01])»
---------Match the regular expression below and capture its match into backreference number 3 «(1[01])»
------------Match the character “1” literally «1»
------------Match a single character present in the list “01” «[01]»
------Or match regular expression number 2 below (the entire group fails if this one fails to match) «[1-9]»
---------Match a single character in the range between “1” and “9” «[1-9]»
---Assert position at a word boundary «\b»

<强> SCREENSHOT

---

这个包含0 - 12

(?<!-)(\b((1[0-2])|[0-9])\b)