Question

我的搜索栏对于tableview有一点问题

我用数组tableViewArray创建了一个tableview tableViewArray由另一个数组组成，包括[text，distance]。一切都很好。
现在我添加了一个searchBar和一个searchdisplaycontroller，它基于一个新的字符串数组（来自tableViewArray的“text”对象）进行搜索。我认为搜索应该只适用于文本，并且搜索方法就是在那里实现的。

现在，当我收到搜索结果时，它看起来不错，搜索会返回预期的行。问题在于搜索tableViews副标题。它显示tableViewArray的第1,2,3行的距离。

我需要它来将距离映射到搜索tableview行中显示的文本。我想我需要为包含[文本距离]的搜索结果创建一个新的表视图数组。文本不是问题，因为它来自搜索结果，但我如何将新距离映射到旧距离？

我在搜索代理中使用的搜索方法是：

searchResults = [[NSArray alloc]init];
NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:@"SELF contains[cd] %@",
                            searchText];
searchResults = [searchItems  filteredArrayUsingPredicate:resultPredicate];

希望有人可以帮忙:)提前谢谢！

原始代码：

- (NSInteger)tableView:(UITableView *)theTableView numberOfRowsInSection:(NSInteger)section
{

    if (theTableView == self.searchDisplayController.searchResultsTableView) {
        return [searchResults count];
    } else {
        return [tableViewArray count];
    }
}  

- (UITableViewCell *)tableView:(UITableView *)theTableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"Cell";

    UITableViewCell *cell = [[UITableViewCell alloc] initWithStyle:     UITableViewCellStyleSubtitle
                                  reuseIdentifier: CellIdentifier] ;

     if (theTableView == self.searchDisplayController.searchResultsTableView) {

    } else {
         cell = [theTableView dequeueReusableCellWithIdentifier:CellIdentifier     forIndexPath:indexPath];
}

    // Configure the cell...
    // cell.textLabel.numberOfLines = 0;
   // cell.textLabel.lineBreakMode = UILineBreakModeWordWrap;

    if (theTableView == self.searchDisplayController.searchResultsTableView) {
        cell.textLabel.text = [searchResults objectAtIndex:indexPath.row];
    } else {
        cell.textLabel.text = [[[tableViewArray objectAtIndex:indexPath.row]     objectAtIndex:0] subtitle];
}

    cell.detailTextLabel.textColor = [UIColor redColor];




float blabla=  [[[tableViewArray objectAtIndex:indexPath.row] objectAtIndex: 1] doubleValue];
if (blabla < 1000) {
         cell.detailTextLabel.text = [NSString stringWithFormat:@"%.2f m",blabla];
} else {
         cell.detailTextLabel.text = [NSString stringWithFormat:@"%.2f km",blabla/1000];
}





NSString *text = [[[tableViewArray objectAtIndex:indexPath.row] objectAtIndex:0] subtitle];
NSRange q8RangeValue = [text rangeOfString:@"Q8" options:NSCaseInsensitiveSearch];
NSRange okRangeValue = [text rangeOfString:@"OK" options:NSCaseInsensitiveSearch];

if (q8RangeValue.length >0  ) {
        cell.imageView.image = [UIImage imageNamed:@"q8.png"];
} else if (okRangeValue.length >0 ) {
        cell.imageView.image = [UIImage imageNamed:@"OK logo.png"];

} else {
        cell.imageView.image = nil;
}

return cell;
}

我在哪里制作搜索阵列：

- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation {

NSLog(@"didUpdateToLocation Location calculator distance array for the tableView");

NSMutableArray * distancesInReverseOrder = [[NSMutableArray alloc] init];



for (int i = 0; i<allAnnotations.count; i++) {

NSIndexPath *indexPath = [NSIndexPath indexPathForRow:i inSection:0] ;
CLLocationCoordinate2D annotationCoord = [[allAnnotations objectAtIndex:indexPath.row] coordinate];


CLLocation *location = [[CLLocation alloc] initWithLatitude:annotationCoord.latitude  longitude:annotationCoord.longitude];

distanceToMe = [newLocation distanceFromLocation:location];

[distancesInReverseOrder insertObject:[NSNumber numberWithFloat: distanceToMe] atIndex:0];

}


distances = [[NSMutableArray alloc] initWithArray:[[distancesInReverseOrder reverseObjectEnumerator] allObjects]];

// Assuming you have your points on the map in an NSArray called
// allAnnotations and your distances in distances, create a
// new mutable array to hold both
tableViewArray = [[NSMutableArray alloc] init];

// Iterate over all of the points, and add a new element to the mutable
// array which is a new array containing a point and its distance
for (int i = 0; i < allAnnotations.count; i++) {
    NSArray *newItem = [NSArray arrayWithObjects: [allAnnotations objectAtIndex: i], [distances objectAtIndex: i], nil];
    [tableViewArray addObject: newItem];
}

// Now, sort the new array based upon the distance in the second element
// of each array (ie, the distance).
[tableViewArray sortUsingComparator: ^(id obj1, id obj2) {
    NSNumber *dist1 = [obj1 objectAtIndex:1];
    NSNumber *dist2 = [obj2 objectAtIndex:1];

    return [dist1 compare:dist2];
}];

searchResults = [NSMutableArray arrayWithCapacity:[tableViewArray count]];




searchItems = [[NSMutableArray alloc] init];

for (int i = 0; i < allAnnotations.count; i++) {
    NSArray *newItem = [NSArray arrayWithObjects: [[[tableViewArray objectAtIndex:i] objectAtIndex:0] subtitle], @"bla", nil];
    [searchItems addObject: newItem];
}

/*
for (int i=0; i<tableViewArray.count; i++) {
    [searchItems insertObject:[[[tableViewArray objectAtIndex:i] objectAtIndex:0] subtitle] atIndex:0];
}
*/

NSLog(@"searchitems count is %i", searchItems.count);

[tableView reloadData];

[locationManager stopUpdatingLocation];

}

    - (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope
{
 /*
// Update the filtered array based on the search text and scope.
// Remove all objects from the filtered search array
[searchResults removeAllObjects];
// Filter the array using NSPredicate
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.name contains[c] %@",searchText];

// searchResults = [NSMutableArray arrayWithArray：[[tableViewArray objectAtIndex：1] filteredArrayUsingPredicate：predicate]];

* /

/*

searchResults = [[NSArray alloc] init];

NSPredicate *resultPredicate = [NSPredicate
                                predicateWithFormat:@"SELF contains[cd] %@",
                                searchText];

    searchResults =[searchItems filteredArrayUsingPredicate:resultPredicate];


*/

// Create index set of all objects in textArray that contain searchText:
NSIndexSet *set = [searchItems indexesOfObjectsPassingTest:
                   ^BOOL(NSString *text, NSUInteger idx, BOOL *stop) {
                       NSRange range = [text rangeOfString:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch)];
                       return (range.location != NSNotFound);
                   }];

// Filter textArray:
filteredTextArray = [searchItems objectsAtIndexes:set];
// Filter distanceArray:
filteredDistanceArray = [distances objectsAtIndexes:set];

NSLog(@"filtered text array is %@", filteredTextArray);
NSLog(@"filtered distance array is %@",filteredDistanceArray);

Answer 1

如果我正确理解您的问题，您有2个单独的数组用作表格视图的数据源，我们称之为textArray和distanceArray。

现在您根据搜索字符串过滤了textArray，您需要对distanceArray进行“对应”过滤。

执行此操作的一种方法是将filteredArrayUsingPredicate替换为indexesOfObjectsPassingTest，因为这会返回一组可应用于两个数组的匹配索引：

// Create index set of all objects in textArray that contain searchText:
NSIndexSet *set = [textArray indexesOfObjectsPassingTest:
    ^BOOL(NSString *text, NSUInteger idx, BOOL *stop) {
        NSRange range = [text rangeOfString:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch)];
        return (range.location != NSNotFound);
    }];

// Filter textArray:
filteredTextArray = [textArray objectsAtIndexes:set];
// Filter distanceArray:
filteredDistanceArray = [distanceArray objectsAtIndexes:set];

现在，您可以使用filteredTextArray和filteredDistanceArray作为搜索表视图的数据源。

或者，如果数组中的每个对象都是一个包含文本和一行距离的字典，则可以使用单个数组作为数据源。

更新：据我所知，tableViewArray的每个项目都是一个包含2个项目的数组（一个用于文本，另一个用于距离）。

在这种情况下，我建议直接过滤tableViewArray：

NSIndexSet *set = [tableViewArray indexesOfObjectsPassingTest:
                   ^BOOL(NSArray *item, NSUInteger idx, BOOL *stop) {
                       NSString *subtitle = [[item objectAtIndex:0] subtitle];
                       NSRange range = [subtitle rangeOfString:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch)];
                       return (range.location != NSNotFound);
                   }];

searchResults = [tableViewArray objectsAtIndexes:set];

现在searchResults是已过滤的数组，每个项目的结构与tableViewArray中的项目相同。

这简化了cellForRowAtIndexPath中的内容，例如

if (theTableView == self.searchDisplayController.searchResultsTableView) {
    cell.textLabel.text = [[[searchResults objectAtIndex:indexPath.row] objectAtIndex:0] subtitle];
     distance = [[[searchResults objectAtIndex:indexPath.row] objectAtIndex: 1] doubleValue];
} else {
    cell.textLabel.text = [[[tableViewArray objectAtIndex:indexPath.row] objectAtIndex:0] subtitle];
    distance = [[[tableViewArray objectAtIndex:indexPath.row] objectAtIndex: 1] doubleValue];
}

uisearchbar uisearchdisplaycontroller tableview字幕错误

1 个答案: