我正在开发Android应用程序。我从以下的uri中获取了recipient_id。
content://mms-sms/conversations?simple=true
现在我想从canonical_addresses " table using the recipient id. But I don't have any idea to query canonical_addresses table"
获取地址。我在网上搜索了很多。请帮我找个解决方案的朋友。
答案 0 :(得分:13)
规范表有两列,_id
和address
。获得收件人ID后,您将在规范地址表中查找该ID。对于多个收件人,ID由空格分隔,因此您必须将结果拆分为
recipient_ids.split(" ")
并查找每个ID。
getContentResolver().query(Uri.parse("content://mms-sms/canonical-addresses"), null, "_id = " + recipientId, null, null);
或
getContentResolver().query(Uri.parse("content://mms-sms/canonical-address/" + recipientId), null, null, null, null);
答案 1 :(得分:2)
message = contentResolver.query(uri, null,null, null,SORT_ORDER);
if(message != null){
while (message.moveToNext()) {
String id = message.getString(message.getColumnIndex("_id"));
String thid = message.getString(message.getColumnIndex("thread_id"));
String phoneNumber = message.getString(message.getColumnIndex("address"));
String person = message.getString(message.getColumnIndex("person"));
//String present = message.getString(message.getColumnIndex("reply_path_present"));
//Log.v("sms "+thid,id);
//Log.v("sms "+present,present);
if(phoneNumber !=null ){
//if(phoneNumber.contains("-"))
phoneNumber=phoneNumber.replaceAll("[-() ]", "");
}
else
{
Cursor c =contentResolver.query(Uri.parse("content://mms-sms/conversations?simple=true"), null, "_id = " + thid, null, null);
//getContentResolver().query(Uri.parse("content://mms-sms/canonical-addresses"), null, "_id = " + recipientId, null, null);
if(c.moveToNext())
{
phoneNumber = c.getString(3);
if(phoneNumber !=null ){
//if(phoneNumber.contains("-"))
Log.v(" id=>" +id+ " thid=>"+thid +" first = > " , c.getString(3));
}
}
c.close();
c =contentResolver.query(Uri.parse("content://mms-sms/canonical-addresses"), null, "_id = " + phoneNumber, null, null);
if(c.moveToNext())
{
Log.v(thid +" second = > " , c.getString(1));
phoneNumber = c.getString(1);
phoneNumber=phoneNumber.replaceAll("[-() ]", "");
}
c.close();