以下是我的数据库结构图:
在这里的用户的帮助下,我设法使用GROUP_CONCAT
整理了一个非常复杂的SQL语句:
SELECT
t1.Name AS Teacher_Name,
t2.Name AS Observer_Name,
o.Datetime AS Datetime,
o.Type AS Type,
o.Year_Group AS Year_Group,
o.Class_Name AS Class_Name,
c.Title AS Course_Name,
GROUP_CONCAT(l.Title) AS Focus,
o.Achievement_Grade AS Achievement_Grade,
o.Behaviour_Grade AS Behaviour_Grade,
o.Teaching_Grade AS Teaching_Grade,
GROUP_CONCAT(cl1.Title) AS Positive,
GROUP_CONCAT(cl2.title) AS Development,
o.Notes AS Notes
FROM observations o
LEFT JOIN teachers t1
ON o.Teacher_ID = t1.Teacher_ID
LEFT JOIN teachers t2
ON o.Observer_ID = t2.Teacher_ID
LEFT JOIN courses c
ON o.Course_ID = c.Course_ID
LEFT JOIN foci f
ON o.ID = f.Observation_ID
LEFT JOIN focus_labels l
on f.focus_id = l.id
LEFT JOIN criteria c1
ON o.ID = c1.Observation_ID
LEFT JOIN criteria_labels cl1
on c1.Criteria_ID = cl1.ID AND c1.Type = 'P'
LEFT JOIN criteria c2
ON o.ID = c2.Observation_ID AND c2.Type = 'D'
LEFT JOIN criteria_labels cl2
on c2.Criteria_ID = cl2.ID
GROUP BY o.id
ORDER BY `Datetime` DESC";
除了根据连接数最多的字段重复Focus
,Positive
和Development
这一事实外,这似乎还可以。
例如,如果Positive
有Pace,Progress,Attainment
但Focus
仅为Appraisal
,则会重复三次(Appraisal,Appraisal,Appraisal
)。
我看了这个,我认为可能是因为我需要GROUP
这些GROUP_CONCAT JOINs
。但是,我不知道如何解决这个问题。
有人可以帮忙吗?提前谢谢,
答案 0 :(得分:1)
GROUP_CONCAT具有DISTINCT属性,可用于删除重复项。
SELECT
t1.Name AS Teacher_Name,
t2.Name AS Observer_Name,
o.Datetime AS Datetime,
o.Type AS Type,
o.Year_Group AS Year_Group,
o.Class_Name AS Class_Name,
c.Title AS Course_Name,
GROUP_CONCAT(DISTINCT l.Title) AS Focus,
o.Achievement_Grade AS Achievement_Grade,
o.Behaviour_Grade AS Behaviour_Grade,
o.Teaching_Grade AS Teaching_Grade,
GROUP_CONCAT(cl1.Title) AS Positive,
GROUP_CONCAT(cl2.title) AS Development,
o.Notes AS Notes
FROM observations o
LEFT JOIN teachers t1
ON o.Teacher_ID = t1.Teacher_ID
LEFT JOIN teachers t2
ON o.Observer_ID = t2.Teacher_ID
LEFT JOIN courses c
ON o.Course_ID = c.Course_ID
LEFT JOIN foci f
ON o.ID = f.Observation_ID
LEFT JOIN focus_labels l
on f.focus_id = l.id
LEFT JOIN criteria c1
ON o.ID = c1.Observation_ID
LEFT JOIN criteria_labels cl1
on c1.Criteria_ID = cl1.ID AND c1.Type = 'P'
LEFT JOIN criteria c2
ON o.ID = c2.Observation_ID AND c2.Type = 'D'
LEFT JOIN criteria_labels cl2
on c2.Criteria_ID = cl2.ID
GROUP BY o.id
ORDER BY `Datetime` DESC";