Question

我只是想在Controller中验证一个我认为很简单的电子邮件地址。我所做的方法如下：

def emailValidCheck(String emailAddress)  {
    EmailValidator emailValidator = EmailValidator.getInstance()
    if (!emailAddress.isAllWhitespace() || emailAddress!=null) {
        String[] email = emailAddress.replaceAll("//s+","").split(",")
        email.each {
            if (emailValidator.isValid(it)) {
            return true
            }else {return false}
        }
    }
}

这与sendMail函数一起使用，我的代码在这里：

def emailTheAttendees(String email) {
    def user = lookupPerson()
    if (!email.isEmpty()) {
        def splitEmails = email.replaceAll("//s+","").split(",")
        splitEmails.each {
            def String currentEmail = it
            sendMail {
                to currentEmail
                System.out.println("what's in to address:"+ currentEmail)
                subject "Your Friend ${user.username} has invited you as a task attendee"
                html g.render(template:"/emails/Attendees")
            }
        }
    }

}

这可以工作并将电子邮件发送到有效的电子邮件地址，但如果我输入一些不是地址的随机内容，则会破坏sendMail异常。我无法理解为什么它没有正确验证甚至进入emailTheAttendees（）方法...这是在save方法中调用的。

Answer 1

我建议使用constraints和a command object来实现这一目标。例如：

命令对象：

@grails.validation.Validateable
class YourCommand {
    String email
    String otherStuffYouWantToValidate

    static constraints = {
        email(blank: false, email: true)
        ...
    }
}

在你的控制器中这样称呼它：

class YourController {
    def yourAction(YourCommand command) {
        if (command.hasErrors()) {
            // handle errors
            return
        }

        // work with the command object data
    }
}

Grails中的电子邮件验证

1 个答案: