我使用ajax将数据从php文件发送到javascript。我想得到像这样的javascript变量。
var members = [
{memberId : 1, parentId:null, amount:200, otherInfo:"blah"},
{memberId : 2, parentId:1, amount:300, otherInfo:"blah1"},
{memberId : 3, parentId:1, amount:400, otherInfo:"blah2"},
{memberId : 4, parentId:3, amount:500, otherInfo:"blah3"},
{memberId : 6, parentId:1, amount:600, otherInfo:"blah4"},
{memberId : 9, parentId:4, amount:700, otherInfo:"blah5"},
{memberId : 12, parentId:2, amount:800, otherInfo:"blah6"},
{memberId : 5, parentId:2, amount:900, otherInfo:"blah7"},
{memberId : 13, parentId:2, amount:0, otherInfo:"blah8"},
{memberId : 14, parentId:2, amount:800, otherInfo:"blah9"},
{memberId : 55, parentId:2, amount:250, otherInfo:"blah10"},
{memberId : 56, parentId:3, amount:10, otherInfo:"blah11"},
{memberId : 57, parentId:3, amount:990, otherInfo:"blah12"},
{memberId : 58, parentId:3, amount:400, otherInfo:"blah13"},
{memberId : 59, parentId:6, amount:123, otherInfo:"blah14"},
{memberId : 54, parentId:6, amount:321, otherInfo:"blah15"},
{memberId : 53, parentId:56, amount:10000, otherInfo:"blah7"},
{memberId : 52, parentId:2, amount:47, otherInfo:"blah17"},
{memberId : 51, parentId:6, amount:534, otherInfo:"blah18"},
{memberId : 50, parentId:9, amount:55943, otherInfo:"blah19"},
{memberId : 22, parentId:9, amount:2, otherInfo:"blah27"},
{memberId : 33, parentId:12, amount:-10, otherInfo:"blah677"}
];
不喜欢json
[{"memberId":"4","parentId":"1","amount":"10","otherInfo":"sds"},{"memberId":"5","parentId":"1","amount":"100","otherInfo":"dsf"},{"memberId":"6","parentId":"4","amount":"1000","otherInfo":"sadsa"}]
答案 0 :(得分:0)
像这样:
<script>
var members = <?php echo json_encode ($members); ?>;
</script>
或者这个:
<script src="source.php"></script>
或者这个:
<script>
jQuery.getJSON ( 'source.php' );
</script>
source.php:
var members = <? echo json_encode ( $members ); ?>
答案 1 :(得分:0)
尝试读取json,然后从中提取数组,在此之前必须创建一个包含所需字段的对象,以便创建它的实例并添加到数组
var items = new Array();
var jsonData = JSON.parse(jsoneString);
for (var i in jsonData) {
var item = jsonData[i];
var prop1 = item.memberId;
//and other items goes here
}
我认为这对你来说是一个合适的解决方案。
答案 2 :(得分:0)
我已经编写了这样的代码,让它正常工作,谢谢大家
response = [{"memberId":"4","parentId":"1","amount":"10","otherInfo":"sds"},{"memberId":"5","parentId":"1","amount":"100","otherInfo":"dsf"},{"memberId":"6","parentId":"4","amount":"1000","otherInfo":"sadsa"}];
response = jQuery.parseJSON(response);
var members = [
{memberId : current_id , parentId:null, name:current_name}
];
for(var i=0; i<response.length;i++){
user = {memberId: parseInt(response[i]['memberId']), parentId: parseInt(response[i]['parentId']), name: response[i]['name']};
members.push(user);
}