Question

请帮帮我:)我有这个代码......

while($row = mysql_fetch_array($result))
{   
$pid=$row ['pid'];
 echo '<div class="single"><div class="wrap">

 <div style="text-align:center;">
     <a href="http://localhost/wordpress/wp-content/themes/snarfer.php?id=<?php echo $pid ?>">Comments</a>

 </br>
<a href="MyOnlineStore/product.php?id=<?php echo $pid?>">View Details</a>
 </div>
 <a href="'.$path.$row['filename'].'" rel="lightbox[plants]" title="'.$row['alttext'].'"><img src="'.$path.$row['filename'].'" alt="Plants: image 1 0f 4 thumb" /></a>
 </div>
</div>';
}

我只是想知道如何回应这个$ pid？ tnxp>

Answer 1

它被认为是一种更好的做法，可以在HTML中回应PHP而不是PHP中的HTML，如下所示：

<?php while($row = mysql_fetch_array($result)): $pid = $row ['pid']; ?>
<div class="single">
    <div class="wrap">
        <div style="text-align:center;">
            <br />
            <a href="MyOnlineStore/product.php?id=<?php echo $pid; ?>">View Details</a>
        </div>
        <a href="<?php echo $path.$row['filename']; ?>" rel="lightbox[plants]" title="<?php echo $row['alttext']; ?>"><img src="<?php echo $path.$row['filename']; ?>" alt="Plants: image 1 0f 4 thumb" /></a>
    </div>
</div>
<?php endwhile; ?>

Answer 2

回答你的问题'如何回应$ pid？'答案是echo $pid;

你也在php中使用php开关标签<?php ?>开启，这将无效。

我建议你阅读http://php.net/manual/en/function.echo.php并熟悉php的基本原理。

另外，正如@Juanid Bhura写的那样

Its considered a better practice to echo PHP within HTML and not HTML within PHP

Answer 3

你的语法错了;你有PHP语法-in- php语法。将您的代码更改为以下内容，它应该可以工作：

echo '<div class="single"><div class="wrap">

<div style="text-align:center;">
 <a href="http://localhost/wordpress/wp-content/themes/snarfer.php?id=' . $pid . '">Comments</a>

</br>
<a href="MyOnlineStore/product.php?id=' . $pid . '">View Details</a>
</div>
<a href="'.$path.$row['filename'].'" rel="lightbox[plants]" title="'.$row['alttext'].'"><img src="'.$path.$row['filename'].'" alt="Plants: image 1 0f 4 thumb" /></a>
</div>
</div>';

Answer 4

希望这有帮助，

<a href="MyOnlineStore/product.php?id='.$pid.'">View Details</a>

引号内的

<?php echo $pid?>被忽略为普通字符串而未被解析。

Answer 5

试试这个：

while($row = mysql_fetch_array($result))
{
    $pid=$row ['pid'];
    echo '<div class="single"><div class="wrap">

 <div style="text-align:center;">
     <a href="http://localhost/wordpress/wp-content/themes/snarfer.php?id='. $pid .'">Comments</a>

 </br>
<a href="MyOnlineStore/product.php?id='.$pid.'">View Details</a>
 </div>
 <a href="'.$path.$row['filename'].'" rel="lightbox[plants]" title="'.$row['alttext'].'"><img src="'.$path.$row['filename'].'" alt="Plants: image 1 0f 4 thumb" /></a>
 </div>
</div>';
}

div中的PHP echo变量

5 个答案: