Question

我正在尝试在iOS 5上使用Twitter Framework进行分享用户将选择要使用的帐户，因此应用将使用所选帐户进行共享。

但是，当performRequestWithHandler返回error

时，null的分享传递给

for (int i = 0; i < [_accountsArray count]; i++) {
//searching for a selected account
            if ([[[_accountsArray objectAtIndex:i] username] isEqualToString:[self getUserName]]) {
                actualUser = [_accountsArray objectAtIndex:i];
                TWRequest *sendTweet = [[TWRequest alloc] initWithURL:[NSURL URLWithString:@"https://upload.twitter.com/1/statuses/update_with_media.json"]
                                                            parameters:nil
                                                        requestMethod:TWRequestMethodPOST];

                [sendTweet addMultiPartData:[text dataUsingEncoding:NSUTF8StringEncoding] withName:@"status" type:@"multipart/form-data"];
                ACAccountStore *account = [[ACAccountStore alloc] init];

                [sendTweet setAccount:[account.accounts objectAtIndex:i]];
                NSLog(@"%@",sendTweet.account);

                [sendTweet performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {

                    NSLog(@"responseData: %@\n",  responseData);
                    NSLog(@"urlResponse: %@\n", urlResponse);
                    NSLog(@"error: %@",error);

                }];
            }
        }

我的代码：

{{1}}

任何人都可以帮助我吗？

由于

Answer 1

现在在iOS上发送推文非常容易。昨晚我更新了我的应用程序，不再使用旧技术，而是使用新的SLComposeViewController技术。下面是我在我的应用程序中的代码片段，允许用户发送带有附加图像的推文。基本上完全相同的代码可用于发布到Facebook。请尝试使用此代码。它还应该允许用户选择他们发送推文的帐户（我也相信这个“默认帐户”发送设置隐藏在电话的设置中）。

if ([SLComposeViewController isAvailableForServiceType:SLServiceTypeTwitter]) {
        SLComposeViewController *mySLComposerSheet = [SLComposeViewController composeViewControllerForServiceType:SLServiceTypeTwitter];
        [mySLComposerSheet setInitialText:@"Sample Tweet Text"];

        //Add the image the user is working with
        [mySLComposerSheet addImage:self.workingImage];

        //Add a URL if desired
        //[mySLComposerSheet addURL:[NSURL URLWithString:@"http://google.com"]];

        //Pop up the post to the user so they can edit and submit
        [self presentViewController:mySLComposerSheet animated:YES completion:nil];

        //Handle the event
        [mySLComposerSheet setCompletionHandler:^(SLComposeViewControllerResult result) {
            switch (result) {
                case SLComposeViewControllerResultCancelled:
                    NSLog(@"Tweet Canceled");
                case SLComposeViewControllerResultDone:
                    NSLog(@"Tweet Done");
                    break;
                default:
                    break;
            }
        }];

    } else {
        //Can't send tweets, show error
        NSLog(@"User doesn't have twitter setup");
    }

TWRequest performRequestWithHandler没有错误，但没有任何反应

1 个答案: