我已经知道图像的位置,但为了简单起见,我想使用JSoup本身下载图像。 (这是为了简化获取cookie,推荐人等)。
这是我到目前为止所做的:
//Open a URL Stream
Response resultImageResponse = Jsoup.connect(imageLocation).cookies(cookies).ignoreContentType(true).execute();
// output here
OutputStreamWriter out = new OutputStreamWriter(new FileOutputStream(new java.io.File(outputFolder + name));
//BufferedWriter out = new BufferedWriter(new FileWriter(outputFolder + name));
out.write(resultImageResponse.body()); // resultImageResponse.body() is where the image's contents are.
out.close();
答案 0 :(得分:44)
在我通过JSoup和一些实验找到答案之前,我甚至没有写完问题。
//Open a URL Stream
Response resultImageResponse = Jsoup.connect(imageLocation).cookies(cookies)
.ignoreContentType(true).execute();
// output here
FileOutputStream out = (new FileOutputStream(new java.io.File(outputFolder + name)));
out.write(resultImageResponse.bodyAsBytes()); // resultImageResponse.body() is where the image's contents are.
out.close();
答案 1 :(得分:1)
只需使用这些方法 -
public static String storeImageIntoFS(String imageUrl, String fileName, String relativePath) {
String imagePath = null;
try {
byte[] bytes = Jsoup.connect(imageUrl).ignoreContentType(true).execute().bodyAsBytes();
ByteBuffer buffer = ByteBuffer.wrap(bytes);
String rootTargetDirectory = IMAGE_HOME + "/"+relativePath;
imagePath = rootTargetDirectory + "/"+fileName;
saveByteBufferImage(buffer, rootTargetDirectory, fileName);
} catch (IOException e) {
e.printStackTrace();
}
return imagePath;
}
public static void saveByteBufferImage(ByteBuffer imageDataBytes, String rootTargetDirectory, String savedFileName) {
String uploadInputFile = rootTargetDirectory + "/"+savedFileName;
File rootTargetDir = new File(rootTargetDirectory);
if (!rootTargetDir.exists()) {
boolean created = rootTargetDir.mkdirs();
if (!created) {
System.out.println("Error while creating directory for location- "+rootTargetDirectory);
}
}
String[] fileNameParts = savedFileName.split("\\.");
String format = fileNameParts[fileNameParts.length-1];
File file = new File(uploadInputFile);
BufferedImage bufferedImage;
InputStream in = new ByteArrayInputStream(imageDataBytes.array());
try {
bufferedImage = ImageIO.read(in);
ImageIO.write(bufferedImage, format, file);
} catch (IOException e) {
e.printStackTrace();
}
}