我的源代码出错,这基本上导致位图图像显得过宽。例如,它将打印宽度和高度,高度是完美的(256),宽度也应该是256,但程序说它是数十亿像素宽,每次都是不同的。这是源代码。
#include "glob.h"
/* Image type - contains height, width, and data */
struct Image {
unsigned long sizeX;
unsigned long sizeY;
char *data;
};
typedef struct Image Image;
int ImageLoad(char *filename, Image *image) {
FILE *file;
unsigned long size; // size of the image in bytes.
unsigned long i; // standard counter.
unsigned short int planes; // number of planes in image (must be 1)
unsigned short int bpp; // number of bits per pixel (must be 24)
char temp; // temporary color storage for bgr-rgb conversion.
// make sure the file is there.
if ((file = fopen(filename, "rb"))==NULL){
printf("bitmap Not Found : %s\n",filename);
return 0;
}
// seek through the bmp header, up to the width/height:
fseek(file, 18, SEEK_CUR);
// read the width
if ((i = fread(&image->sizeX, 4, 1, file)) != 1) {
printf("Error reading width from %s.\n", filename);
return 0;
}
printf("Width of %s: %lu\n", filename, image->sizeX);
// read the height
if ((i = fread(&image->sizeY, 4, 1, file)) != 1) {
printf("Error reading height from %s.\n", filename);
return 0;
}
printf("Height of %s: %lu\n", filename, image->sizeY);
// calculate the size (assuming 24 bits or 3 bytes per pixel).
size = image->sizeX * image->sizeY * 3;
// read the planes
if ((fread(&planes, 2, 1, file)) != 1) {
printf("Error reading planes from %s.\n", filename);
return 0;
}
if (planes != 1) {
printf("Planes from %s is not 1: %u\n", filename, planes);
return 0;
}
// read the bpp
if ((i = fread(&bpp, 2, 1, file)) != 1) {
printf("Error reading bpp from %s.\n", filename);
return 0;
}
if (bpp != 24) {
printf("Bpp from %s is not 24: %u\n", filename, bpp);
return 0;
}
// seek past the rest of the bitmap header.
fseek(file, 24, SEEK_CUR);
// read the data.
image->data = (char *) malloc(size);
if (image->data == NULL) {
printf("Error allocating memory for color-corrected image data\n");
return 0;
}
if ((i = fread(image->data, size, 1, file)) != 1) {
printf("Error reading image data from %s.\n", filename);
return 0;
}
for (i=0; i<size; i+=3) { // reverse all of the colors. (bgr -> rgb)
temp = image->data[i];
image->data[i] = image->data[i+2];
image->data[i+2] = temp;
}
// we're done.
return 0;
}
// Load Bitmaps And Convert To Textures
void glob::LoadGLTextures() {
// Load Texture
Image *image1;
// allocate space for texture
image1 = (Image *) malloc(sizeof(Image));
if (image1 == NULL) {
printf("(image1 == NULL)\n");
exit(0);
}
ImageLoad("data/textures/NeHe.bmp", image1);
// Create Texture
glGenTextures(1, &texture);
glBindTexture(GL_TEXTURE_2D, texture); // 2d texture (x and y size)
glTexParameteri(GL_TEXTURE_2D,GL_TEXTURE_MAG_FILTER,GL_LINEAR); // scale linearly when image bigger than texture
glTexParameteri(GL_TEXTURE_2D,GL_TEXTURE_MIN_FILTER,GL_LINEAR); // scale linearly when image smalled than texture
// 2d texture, level of detail 0 (normal), 3 components (red, green, blue), x size from image, y size from image,
// border 0 (normal), rgb color data, unsigned byte data, and finally the data itself.
glTexImage2D(GL_TEXTURE_2D, 0, 3, image1->sizeX, image1->sizeY, 0, GL_RGB, GL_UNSIGNED_BYTE, image1->data);
};
glob.h是这样的:
#ifndef GLOB_H_INCLUDED
#define GLOB_H_INCLUDED
#include <iostream>
#include <stdlib.h>
#include <stdio.h> // Header file for standard file i/o.
#include <GL/glx.h> /* this includes the necessary X headers */
#include <GL/gl.h>
//#include <GL/glut.h> // Header File For The GLUT Library
//#include <GL/glu.h> // Header File For The GLu32 Library
#include <X11/X.h> /* X11 constant (e.g. TrueColor) */
#include <X11/keysym.h>
class glob {
bool Running;
GLuint texture; //make an array when we start using more then 1
Display *dpy;
Window win;
XEvent event;
GLboolean doubleBuffer;
GLboolean needRedraw;
GLfloat xAngle, yAngle, zAngle;
float camera_x, camera_y, camera_z;
public:
glob();
int OnExecute();
public:
int init(int argc, char **argv);
void LoadGLTextures();
void OnEvent();
void redraw(void);
};
#endif // GLOB_H_INCLUDED
任何人都可以帮我解决这个问题吗?
答案 0 :(得分:2)
很多事情都可能出错。
如果它是一个非常旧的文件,它可能有一个BITMAPCOREHEADER
,其大小字段每个只有2个字节。
你的机器是小端吗? BMP文件以little endian存储。
请注意,高度可能是负数(这意味着它是一个自上而下的位图,而不是自下而上的位图)。如果将小的负数解释为无符号的32位int,您将看到数十亿的值。
此外,您对实际像素数据的搜索假定它在位图标题之后立即开始。这很常见,但不是必需的。 file header包含实际像素数据的偏移量。 (Microsoft文档将其称为“位图位”或“颜色数据”。)
我建议您对文件的开头执行十六进制转储,然后手动逐步执行,以确保所有偏移和假设都正确无误。您可以随意将十六进制转储的开头粘贴到您的问题中。
你在Windows上吗?你能打电话给LoadImage
吗?