2019 ...

Question

我们是否可以为UILabel启用UITextField的剪切复制粘贴菜单？
如果没有，我需要将UILabel转换为UITextField，如何启用剪切复制粘贴菜单并且不允许修改内容？
< / LI>

Answer 1

我得到了副本＆amp;粘贴菜单工作在UILabel，我只需返回YES canBecomeFirstResponder，然后在屏幕上显示所述标签时调用[label becomeFirstResponder]。对于从YES返回canBecomeFirstResponder，您可以使用类别创建自定义子类或补丁UILabel：

@implementation UILabel (Clipboard)

- (BOOL) canBecomeFirstResponder
{
    return YES;
}

@end

类别解决方案感觉有点hackish，但如果你知道你在做什么，它可能比继承更容易。我还提出了sample project on GitHub，其中显示了如何在UILabel上显示简单的粘贴板菜单。

Answer 2

对于Swift 3和Swift 4，你必须实现这个类：

import UIKit

class CopyableLabel: UILabel {

    override init(frame: CGRect) {
        super.init(frame: frame)
        self.sharedInit()
    }

    required init?(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)
        self.sharedInit()
    }

    func sharedInit() {
        self.isUserInteractionEnabled = true
        self.addGestureRecognizer(UILongPressGestureRecognizer(target: self, action: #selector(self.showMenu)))
    }

    @objc func showMenu(sender: AnyObject?) {
        self.becomeFirstResponder()

        let menu = UIMenuController.shared

        if !menu.isMenuVisible {
            menu.setTargetRect(bounds, in: self)
            menu.setMenuVisible(true, animated: true)
        }
    }

    override func copy(_ sender: Any?) {
        let board = UIPasteboard.general

        board.string = text

        let menu = UIMenuController.shared

        menu.setMenuVisible(false, animated: true)
    }

    override var canBecomeFirstResponder: Bool {
        return true
    }

    override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
        return action == #selector(UIResponderStandardEditActions.copy)
    }
}

在您的故事板中，只需将UILabel与CopyableLabel类

进行子类化

Answer 3

由于@ zoul的答案，sample project on github是要走的路。在撰写本文时，该项目实际上并未在剪贴板（粘贴板）上放置任何内容。这是如何：

将@ zoul的此方法实现更改为：

- (void) copy:(id)sender {
    UIPasteboard *pboard = [UIPasteboard generalPasteboard];
    pboard.string = self.text;  
}

Answer 4

Swift 4☻Xcode 9.2 。使用UIMenuController我们可以做到。

我创建了IBDesignable自定义UILabel课程，您可以直接在故事板上分配

@IBDesignable
class TapAndCopyLabel: UILabel {

    override func awakeFromNib() {
        super.awakeFromNib()
        //1.Here i am Adding UILongPressGestureRecognizer by which copy popup will Appears
        let gestureRecognizer = UILongPressGestureRecognizer(target: self, action: #selector(handleLongPressGesture(_:)))
        self.addGestureRecognizer(gestureRecognizer)
        self.isUserInteractionEnabled = true
    }

    // MARK: - UIGestureRecognizer
    @objc func handleLongPressGesture(_ recognizer: UIGestureRecognizer) {
        guard recognizer.state == .recognized else { return }

        if let recognizerView = recognizer.view,
            let recognizerSuperView = recognizerView.superview, recognizerView.becomeFirstResponder()
        {
            let menuController = UIMenuController.shared
            menuController.setTargetRect(recognizerView.frame, in: recognizerSuperView)
            menuController.setMenuVisible(true, animated:true)
        }
    }
    //2.Returns a Boolean value indicating whether this object can become the first responder
    override var canBecomeFirstResponder: Bool {
        return true
    }
    //3.Here we are enabling copy action
    override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
        return (action == #selector(UIResponderStandardEditActions.copy(_:)))

    }
    // MARK: - UIResponderStandardEditActions
    override func copy(_ sender: Any?) {
        //4.copy current Text to the paste board
        UIPasteboard.general.string = text
    }
}

<强>输出：

Answer 5

我已经创建了一个开源UILabel子类，它显示了长按时带有“复制”选项的UIMenuController：

GitHub上的

HTCopyableLabel

Answer 6

如果有人仍然感兴趣，我已经分享了zoul的示例项目，并增加了对ARC（以及其他一些功能）的支持：

https://github.com/zhbrass/UILabel-Clipboard

CopyLabel.h / .m应该是你要找的东西

Answer 7

覆盖UITextField实例的textFieldShouldBeginEditing方法，并将其设置为返回NO以禁用编辑。

查看UITextFieldDelegate协议了解更多详情。

Answer 8

如果您有多行文字，则应使用input

设置代理：

UITextView

它应该神奇地工作：）

Answer 9

2019 ...

保存输入的任何人

public class SomeComplexCustomView: UIView {

    @IBOutlet var oneOfYourLabels: UILabel!
    ... your other labels, boxes, etc

    public func makeThatLabelCopyable() {
        oneOfYourLabels.isUserInteractionEnabled = true
        addGestureRecognizer(UITapGestureRecognizer(
          target: self, action: #selector(self.copyMenu(sender:))))
        addGestureRecognizer(UILongPressGestureRecognizer(
          target: self, action: #selector(self.copyMenu(sender:))))

        // or use oneOfYourLabels.addGesture... to touch just on that item 
    }

    public override var canBecomeFirstResponder: Bool { return true }

    @objc func copyMenu(sender: Any?) {
        becomeFirstResponder()
        UIMenuController.shared.setTargetRect(bounds, in: self)
        // or any exact point you want the pointy box pointing to
        UIMenuController.shared.setMenuVisible(true, animated: true)
    }

    override public func copy(_ sender: Any?) {
        UIPasteboard.general.string = oneOfYourLabels.text
        // or any exact text you wish
        UIMenuController.shared.setMenuVisible(false, animated: true)
    }

    override public func canPerformAction(
      _ action: Selector, withSender sender: Any?) -> Bool {
        return (action == #selector(copy(_:)))
    }
}

就这么简单！

Answer 10

Swift 5.3和SwiftUI

要在SwiftUI中实现此目的，我们可以使用pableiros创建与UIViewRepresentable组合的方法。

我们需要对CopyableLabel类进行两次更新，因为iOS 13中不推荐使用以下方法。

.setTargetRect(_,in:)

.setMenutVisible(_,animated)

我们可以使用.showMenu(from:rect:)方法轻松地解决此问题。

这是更新的CopyableLabel类。

class CopyableLabel: UILabel {

    override init(frame: CGRect) {
        super.init(frame: frame)
        self.sharedInit()
    }

    required init?(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)
        self.sharedInit()
    }

    func sharedInit() {
        self.isUserInteractionEnabled = true
        self.addGestureRecognizer(UILongPressGestureRecognizer(target: self, action: #selector(self.showMenu)))
    }

    @objc func showMenu(sender: AnyObject?) {
        self.becomeFirstResponder()

        let menu = UIMenuController.shared

        if !menu.isMenuVisible {
            menu.showMenu(from: self, rect: self.bounds) // <-  we update the deprecated methods here
        }
    }

    override func copy(_ sender: Any?) {
        let board = UIPasteboard.general

        board.string = text

        let menu = UIMenuController.shared

        menu.showMenu(from: self, rect: self.bounds) // <- we update the deprecated methods here
    }

    override var canBecomeFirstResponder: Bool {
        return true
    }

    override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
        return action == #selector(UIResponderStandardEditActions.copy)
    }
}

然后使该类与SwiftUI一起使用，我们要做的就是创建一个简单的UIViewRepresentable。

struct CopyableLabelView: UIViewRepresentable {

    let text: String
    private let label = CopyableLabel(frame: .zero)

    init(text: String) {
        self.text = text
    }

    func makeUIView(context: Context) -> UILabel {
        // Set the text for the label
        label.text = text

        // Set the content hugging priority so the UILabel's view is
        // kept tight to the text.
        label.setContentHuggingPriority(.required, for: .horizontal)
        label.setContentHuggingPriority(.required, for: .vertical)
        return label
    }

    func updateUIView(_ uiView: UILabel, context: Context) {
        // Handle when the text that is passed changes
        uiView.text = text
    }
}

Answer 11

@benvolioT's github project是复制的好例子。对于粘贴，请自定义canPerformAction:withSender:。有关详细信息，请参阅示例CopyPasteTile。

Answer 12

在 Swift 5.0 和 Xcode 10.2

中

直接在ViewController中将复制选项添加到UILabel。

//This is your UILabel
@IBOutlet weak var lbl: UILabel!

//In your viewDidLoad()
self.lbl.isUserInteractionEnabled = true
let longPress = UILongPressGestureRecognizer.init(target: self, action: #selector((longPressFunctin(_:))))
self.lbl.addGestureRecognizer(longPress)

//Write these all functions outside the viewDidLoad()
@objc func longPressFunctin(_ gestureRecognizer: UILongPressGestureRecognizer) {
    lbl.becomeFirstResponder()
    let menu = UIMenuController.shared
    if !menu.isMenuVisible {
        menu.setTargetRect(CGRect(x: self.lbl.center.x, y: self.lbl.center.y, width: 0.0, height: 0.0), in: view)
        menu.setMenuVisible(true, animated: true)
    }
}

override func copy(_ sender: Any?) {
    let board = UIPasteboard.general
    board.string = lbl.text
}

override var canBecomeFirstResponder: Bool {
    return true
}

override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
    return action == #selector(copy(_:))
}

在UILabel上显示iPhone剪切复制粘贴菜单

12 个答案:

2019 ...

Swift 5.3和SwiftUI