我试过
UPDATE TABLENAME SET COLUMNNAME = REPLACE(COLUMNNAME, '\t', '')
但我不知道如何在t-sql中编写TAB
答案 0 :(得分:43)
标签的ASCII代码是9;你可以尝试
update tablename set columnname = replace(columnname, char(9), '')
答案 1 :(得分:23)
适用于TAB
和ENTER
SELECT
-- TRIM
LTRIM(RTRIM(REPLACE(REPLACE(REPLACE(columnname, CHAR(9), ' '), CHAR(13), ' '), CHAR(10), ' ')))
答案 2 :(得分:12)
在我的TSql sProcs的开头,我经常把
Declare @nl Char(2) = char(13) + char(10)
Declare @tab Char(1) = char(9)
etc...
然后你可以在proc的其余部分的任何地方使用那些声明的变量,而不会失去清晰度......
答案 3 :(得分:4)
您可以在字符串中添加制表符,只需按Tab键即可。
这样可行,但不太可读。
答案 4 :(得分:3)
我找到了解决方案:
在T-SQL中,您不会转义字符,而是将它们直接粘贴或键入引号。它甚至适用于\ r \ n(回车,新行=你按回车)
答案 5 :(得分:2)
我在上面尝试过的评论之一只是读取数据,而没有实际更新数据,我在以下方面取得了最大的成功
UPDATE Tbl
SET Tbl.[ColumnName] = LTRIM(RTRIM(REPLACE(REPLACE(REPLACE(Tbl.[ColumnName], CHAR(9), ' '),CHAR(13), ' '),CHAR(10), ' ')))
FROM [TableName] AS Tbl
我知道这是一个古老的问题,希望对别人有帮助
答案 6 :(得分:1)
签出此功能。这将删除所有无效字符
-- =============================================
-- Author: xenoivan
-- Description: clean invalid chars
-- =============================================
CREATE FUNCTION [dbo].[fnClean]
(
@in NVARCHAR(MAX)
)
RETURNS NVARCHAR(MAX)
AS
BEGIN
-- Declare the return variable here
DECLARE @out NVARCHAR(MAX)
-- Add the T-SQL statements to compute the return value here
SELECT @out = REPLACE(@in,N'َ','')
SELECT @out = REPLACE(@out,char(9),'')
SELECT @out = REPLACE(@out,char(13),'')
SELECT @out = REPLACE(@out,char(10),'')
SELECT @out = REPLACE(@out,N'','')
SELECT @out = REPLACE(@out,N'','')
SELECT @out = REPLACE(@out,N'','')
SELECT @out = REPLACE(@out,N'', '')--its a hidden character
SELECT @out = REPLACE(@out,N'', '')--ltr code
SELECT @out = REPLACE(@out,N'', '')--rtl code
SELECT @out = REPLACE(@out,N'۰', '0')
SELECT @out = REPLACE(@out,N'۱', '1')
SELECT @out = REPLACE(@out,N'۲', '2')
SELECT @out = REPLACE(@out,N'۳', '3')
SELECT @out = REPLACE(@out,N'۴', '4')
SELECT @out = REPLACE(@out,N'۵', '5')
SELECT @out = REPLACE(@out,N'۶', '6')
SELECT @out = REPLACE(@out,N'۷', '7')
SELECT @out = REPLACE(@out,N'۸', '8')
SELECT @out = REPLACE(@out,N'۹', '9')
SELECT @out = REPLACE(@out,N'٠', '0')
SELECT @out = REPLACE(@out,N'١', '1')
SELECT @out = REPLACE(@out,N'٢', '2')
SELECT @out = REPLACE(@out,N'٣', '3')
SELECT @out = REPLACE(@out,N'٤', '4')
SELECT @out = REPLACE(@out,N'٥', '5')
SELECT @out = REPLACE(@out,N'٦', '6')
SELECT @out = REPLACE(@out,N'٧', '7')
SELECT @out = REPLACE(@out,N'٨', '8')
SELECT @out = REPLACE(@out,N'٩', '9');
-- Return the result of the function
RETURN @out
END