我正在使用Postgresql DB。
我想对表中的数字列执行查询,以查找该值是否以特定数字开头。
我目前有:
SELECT * FROM myTable WHERE to_char(ID, '12345678') LIKE '2%'
但是这会返回一个空数据集(但ID列中的值以2开头。
非常感谢
史蒂夫
答案 0 :(得分:2)
这是因为TO_CHAR
中数字的模式是9
(具有指定位数的值)或0
(带前导零的值)。使用以下内容:
SELECT * FROM myTable WHERE TRIM(to_char(ID, '99999999')) LIKE '2%'
或者将数字转换为字符。
答案 1 :(得分:2)
SELECT * FROM mytable
WHERE id = 2
OR (id >=20 AND id < 30)
OR (id >=200 AND id < 300)
OR (id >=2000 AND id < 3000)
OR (id >=20000 AND id < 30000)
OR (id >=200000 AND id < 300000)
OR (id >=2000000 AND id < 3000000)
OR (id >=20000000 AND id < 30000000)
OR (id >=200000000 AND id < 300000000)
OR (id >=2000000000 AND id < 3000000000)
OR (id >=20000000000 AND id < 30000000000)
OR (id >=200000000000 AND id < 300000000000)
-- ...
;
这可能导致postgres生成更好的查询计划,因为可以使用索引(如果存在,可以预期id字段)
更新: 查询计划:
Bitmap Heap Scan on reservations (cost=1838.15..13290.11 rows=110809 width=4012) (actual time=11.310..24.379 rows=111111 loops=1)
Recheck Cond: ((id = 2) OR ((id >= 20) AND (id < 30)) OR ((id >= 200) AND (id < 300)) OR ((id >= 2000) AND (id < 3000)) OR ((id >= 20000) AND (id < 30000)) OR ((id >= 200000) AND (id < 300000)) OR ((id >= 2000000) AND (id < 3000000)) OR ((id >= 20000000) AND (id < 30000000)) OR ((id >= 200000000) AND (id < 300000000)) OR ((id >= 2000000000) AND (id < 3000000000::bigint)) OR ((id >= 20000000000::bigint) AND (id < 30000000000::bigint)) OR ((id >= 200000000000::bigint) AND (id < 300000000000::bigint)))
-> BitmapOr (cost=1838.15..1838.15 rows=112192 width=0) (actual time=11.242..11.242 rows=0 loops=1)
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1.49 rows=1 width=0) (actual time=0.005..0.005 rows=1 loops=1)
Index Cond: (id = 2)
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1.58 rows=10 width=0) (actual time=0.003..0.003 rows=10 loops=1)
Index Cond: ((id >= 20) AND (id < 30))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..2.52 rows=104 width=0) (actual time=0.013..0.013 rows=100 loops=1)
Index Cond: ((id >= 200) AND (id < 300))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..14.24 rows=1036 width=0) (actual time=0.110..0.110 rows=1000 loops=1)
Index Cond: ((id >= 2000) AND (id < 3000))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..144.73 rows=10845 width=0) (actual time=1.050..1.050 rows=10000 loops=1)
Index Cond: ((id >= 20000) AND (id < 30000))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1332.24 rows=100196 width=0) (actual time=10.013..10.013 rows=100000 loops=1)
Index Cond: ((id >= 200000) AND (id < 300000))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1.49 rows=1 width=0) (actual time=0.010..0.010 rows=0 loops=1)
Index Cond: ((id >= 2000000) AND (id < 3000000))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1.49 rows=1 width=0) (actual time=0.001..0.001 rows=0 loops=1)
Index Cond: ((id >= 20000000) AND (id < 30000000))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1.49 rows=1 width=0) (actual time=0.001..0.001 rows=0 loops=1)
Index Cond: ((id >= 200000000) AND (id < 300000000))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1.49 rows=1 width=0) (actual time=0.002..0.002 rows=0 loops=1)
Index Cond: ((id >= 2000000000) AND (id < 3000000000::bigint))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1.49 rows=1 width=0) (actual time=0.026..0.026 rows=0 loops=1)
Index Cond: ((id >= 20000000000::bigint) AND (id < 30000000000::bigint))
-> Bitmap Index Scan on reservations_pkey (cost=0.00..1.49 rows=1 width=0) (actual time=0.002..0.002 rows=0 loops=1)
Index Cond: ((id >= 200000000000::bigint) AND (id < 300000000000::bigint))
Total runtime: 28.720 ms
(28 rows)
Seq Scan on reservations (cost=0.00..19219.52 rows=4383 width=4012) (actual time=0.025..184.532 rows=111111 loops=1)
Filter: ((id)::text ~~ '2%'::text)
Total runtime: 189.100 ms
(3 rows)
答案 2 :(得分:2)
这将返回前导数字:
floor(a/10.^(floor(log(a))))
示例:
select a from generate_series(1,1000) as a where
floor(a/10.^(floor(log(a)))) = 2;
如果您的数字小于1或小于零,则应将其过滤掉(具体取决于您的要求)。
答案 3 :(得分:0)
我找到了答案:
SELECT * FROM myTable WHERE CAST (ID AS CHAR) LIKE '2%'
史蒂夫
答案 4 :(得分:-1)
您不需要to_char
,只需id like '2%'
。