我有简单的应用程序,我需要从MySQL获取数据。我读到我可以使用* .php文件中的服务器上的脚本来完成它,我需要做的只是从我的qooxdoo应用程序运行此文件并获取打印数据。这是一段代码:
doWysyl.addListener("execute", function(e) //doWysyl is button
{
var req = new qx.io.remote.Request("http://localhost/db_connector.php", "GET", "application/json");
req.addListener("completed", function(e)
{
alert("Something");
});
req.send();
}, this);
db_connector.php文件:
<?php
$db = mysql_connect('localhost', 'root', '');
if (!$link) {
die('Can't connect: ' . mysql_error());
}
$result = mysql_query("SELECT Id FROM gitterbox WHERE Ukryj=0")
$dane = array();
while ($row = mysql_fetch_assoc($result)) {
$dane [] = $row["Id"];
}
mysql_close($link);
echo json_encode($dane);
?>
我的问题是警报(“Something”);从来没有表现出像完成的事件永远不会被解雇。我也试过了不同的活动,但都没有帮助。我确定db_connect.php已打开,因为我已经检查过了。
好的,我编辑了我的代码以使用Xhr请求,现在它看起来像:
doWysyl.addListener("execute", function(e) {
var req = new qx.io.request.Xhr("http://localhost/db_connector.php", "GET");
req.addListener("success", function(e) {
alert("success");
}, this);
req.addListener("fail", function(e) {
var reqa = e.getTarget()
var response = req.getResponse()
alert("fail "+response+". Code: "+reqa.getStatus())
}, this);
req.send();
}, this);
但问题是我总是遇到失败事件并且在警报中我有消息:
fail null. Code 0
我在警报之前添加了断点,并且是堆栈跟踪(使用Chrome和Windows 7 x64):
(anonymous function) (class/custom/MainWindow.js:27)
qx.Class.define.members.dispatchEvent (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/event/dispatch/Direct.js:134)
wrappedFunction (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/Interface.js:451)
qx.Class.define.members.dispatchEvent (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/event/Manager.js:873)
qx.Class.define.statics.fireEvent (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/event/Registration.js:310)
qx.Mixin.define.members.fireEvent (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/core/MEvents.js:169)
qx.Class.define.members._onError (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/io/request/AbstractRequest.js:773)
(anonymous function) (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/lang/Function.js:293)
qx.Bootstrap.define.members._emit (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/bom/request/Xhr.js:440)
qx.Bootstrap.define.members.__readyStateChangeDone (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/bom/request/Xhr.js:897)
qx.Bootstrap.define.members.__readyStateChange (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/bom/request/Xhr.js:869)
qx.Bootstrap.define.members.__onNativeReadyStateChange (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/bom/request/Xhr.js:808)
(anonymous function) (/D:/qooxdoo-2.0.2-sdk/framework/source/class/qx/Bootstrap.js:551)
我觉得有趣的是this,在网络标签中。我希望有所帮助。
答案 0 :(得分:1)
首先,我建议使用qx.io.request.Xhr:
您将在此页面上详细了解如何使用它:
http://manual.qooxdoo.org/1.5/pages/communication/request_io.html
如果你使用Xhr,我会建议听“成功”和“失败”或“statusError”。 这会给你一些关于你的要求的错误。