我在SQL服务器中有两个日期,两个月重叠我想知道每个月的圈数。 例如:
Start date is : 26-Sep-2012
End Date is : 10-Oct-2012
Sept- 5 days
October - 10 days
以及每个月的日期列表。
答案 0 :(得分:2)
declare @start datetime;
declare @end datetime;
set @start = '20120926';
set @end = '20121010';
SELECT (DAY(DATEADD (m, 1, DATEADD(d, 1 - DAY(@start), @start))-1)
- DAY(@start) + 1) AS DaysLeftStart,
DAY(@end) AS DaysEnd
答案 1 :(得分:0)
DECLARE @start DATETIME, @end DATETIME;
SELECT @start = '20120926', @end = '20121010';
;WITH c(d) AS
(
SELECT TOP (DATEDIFF(DAY, @start, @end)+1)
DATEADD(DAY, ROW_NUMBER() OVER (ORDER BY name)-1, @start)
FROM sys.all_columns
)
SELECT
[date] = DATEADD(MONTH, DATEDIFF(MONTH, 0, d), 0),
[days] = COUNT(*)
FROM c GROUP BY DATEDIFF(MONTH, 0, d)
UNION ALL SELECT d, NULL FROM c;
结果:
date days
----------------------- -----
2012-09-01 00:00:00.000 5
2012-10-01 00:00:00.000 10
2012-09-26 00:00:00.000 NULL
2012-09-27 00:00:00.000 NULL
2012-09-28 00:00:00.000 NULL
2012-09-29 00:00:00.000 NULL
2012-09-30 00:00:00.000 NULL
2012-10-01 00:00:00.000 NULL
2012-10-02 00:00:00.000 NULL
2012-10-03 00:00:00.000 NULL
2012-10-04 00:00:00.000 NULL
2012-10-05 00:00:00.000 NULL
2012-10-06 00:00:00.000 NULL
2012-10-07 00:00:00.000 NULL
2012-10-08 00:00:00.000 NULL
2012-10-09 00:00:00.000 NULL
2012-10-10 00:00:00.000 NULL
答案 2 :(得分:-1)
Here您可以找到有关创建日历表的详细信息。您可以使用它来执行此类查询:
SELECT CalendarMonth, count(*) day_num
FROM dbo.Calendar
WHERE CalendarDate between @start_date and @end_date;