需要帮助设置json数组

时间:2012-09-15 21:24:03

标签: php javascript arrays json jsonp

数据库查询返回几行,我按如下方式循环:

    foreach ($query->result() as $row) {

        $data[$row->post_id]['post_id']         = $row->post_id;
        $data[$row->post_id]['post_type']       = $row->post_type;
        $data[$row->post_id]['post_text']       = $row->post_text;
    }

如果我json_encode生成的数组($a['stream'])我得到了

{
    "stream": {
        "1029": {
            "post_id": "1029",
            "post_type": "1",
            "post_text": "bla1",
        },
        "1029": {
            "post_id": "1030",
            "post_type": "3",
            "post_text": "bla2",
        },
        "1029": {
            "post_id": "1031",
            "post_type": "2",
            "post_text": "bla3",            
        }
    }
}

但是json实际上应该是这样的:

{
    "stream": {
        "posts": [{
            "post_id": "1029",
            "post_type": "1",
            "post_text": "bla1",
        },
        {
            "post_id": "1030",
            "post_type": "3",
            "post_text": "bla2",
        },
        {
            "post_id": "1031",
            "post_type": "2",
            "post_text": "bla3",            
        }]
    }
}

我应该如何构建我的数组以使json正确?

3 个答案:

答案 0 :(得分:1)

无论如何,这是你应该做的:

...
$posts = array();
foreach ($query->result() as $row) {
    $post = array();
    $post['post_id']         = $row->post_id;
    $post['post_type']       = $row->post_type;
    $post['post_text']       = $row->post_text;
    $posts[] = $post;
}
$data['posts'] = $posts;
...

一点解释:您必须根据从数据库获取的信息构建一个对象,即$post。需要将这些对象中的每一个添加到一个数组中,即$posts。来自数据库的这一系列帖子设置为posts的密钥$data,即$data['posts']

答案 1 :(得分:1)

这个怎么样?

http://codepad.viper-7.com/zPHCm0

<?php
$myData = array();
$myData['posts'][] = array('post_id' => 3, 'post_type' => 343, 'post_text' => 'sky muffin pie');
$myData['posts'][] = array('post_id' => 4, 'post_type' => 111, 'post_text' => 'Mushroom chocolate banana');
$myData['posts'][] = array('post_id' => 231, 'post_type' => 888, 'post_text' => 'Cucumber strawberry in the sky');

$theStream['stream'] = $myData;

$json = json_encode($theStream);

echo 'JSON:<Br/>';
echo $json;

上面给了我:

{
    "stream":
    {   "posts":[
            {"post_id":3,"post_type":343,"post_text":"sky muffin pie"},
            {"post_id":4,"post_type":111,"post_text":"Mushroom chocolate banana"},
            {"post_id":231,"post_type":888,"post_text":"Cucumber strawberry in the sky"}]
    }
} 

答案 2 :(得分:0)

foreach ($query->result() as $row) {
    $data['posts']['post_id']         = $row->post_id;
    $data['posts']['post_type']       = $row->post_type;
    $data['posts']['post_text']       = $row->post_text;
}