Question

我有三张桌子：

1. user    => user_id[Pk], user_name
2. payment => payment_id[PK], user_id[FK], amount
3. receive => receive_id[PK], user_id[FK], amount

现在我想获取像：

这样的记录

用户名，paymentamount，receivableamount

提前致谢..

我已阅读this，但它对我不起作用。

假设，在用户表

中

USER_ID USER_NAME
1 ABC
2 XYZ

在付款表

中

payment_id USER_ID量
1个1 1000
2个1 200
3个2 150

在接收表中：
receive_id USER_ID量
1个2 100
2 1 200

现在我想要像

这样的记录

USER_NAME paymentamount receivableamount
ABC 1000 200
ABC 200
XYZ 150 100

Answer 1

您可能希望按user_id汇总金额。

SELECT
    user.user_id,
    SUM(payment.amount) AS payment_amount,
    SUM(receive.amount) AS receive_amount
FROM (receive INNER JOIN [user] ON receive.user_id = user.user_id)
              INNER JOIN payment ON user.user_id = payment.user_id
GROUP BY user.user_id;

Answer 2

使用内置查询设计器。将三个表拖入其中，链接键（将字段拖放到彼此），双击要将其添加到底部字段列表的字段，然后运行查询。如果需要，请选择聚合表达式。

Answer 3

您可能需要根据MSAccess语法进行调整，但其目的是执行LEFT JOIN付款并接收带有用户的表，因为这是父表，而其他两个表可能有也可能没有这个用户。

SELECT 
    u.user_name, 
    ISNULL(p.amount, 0) as paymentamount,
    ISNULL(r.amount, 0) as receivableamount
FROM 
    user u
    LEFT JOIN payment p
    ON u.user_id = p.user_id
    LEFT JOIN receive r
    ON u.user_id = r.user_id

Answer 4

select 
    user.user_name, payment.amount, receive.amount 
from user 
    join payment on user.user_id == payment.user_id 
    join receive on user.user_id = receive.user_id;

Answer 5

select t1.user_name, t2.amount payementamount, t3.amount receiveableamount from 
User t1,
payment t2,
receive t3
where
t1.user_id=t2.user_id and
t1.user_id=t3.user_id

你可以尝试一下......

使用访问数据库组合三个表

5 个答案: