This thread是金牌。它似乎相对简单,我真的很喜欢它,但它似乎也使用一个非命名的锁,我需要一个进程间解决方案(不需要是可移植的,可以只有Windows)。
有没有办法进行进程间shared_mutex
?我看到有一个named_mutex
但我无法使用shared_lock
其他锁定。
任何指针都表示赞赏。
[编辑]
与此同时,我遇到this thread几乎击中头部的钉子。我有两个问题:
named_upgradable_mutex
但我不太确定)和仍然欢迎评论或好的解决方案。
答案 0 :(得分:10)
Boost.Interprocess文档描述了它支持的所谓upgradable mutexes和两个支持的可升级互斥锁类型的upgradable mutex operations:
boost::interprocess::interprocess_upgradable_mutex
,一种非递归,匿名可升级的互斥锁,可放置在共享内存或内存映射文件中。boost::interprocess::named_upgradable_mutex
,一种非递归的,名为可升级的互斥锁。编辑:我相信这有效:
#include <iostream>
#include <string>
#include <unistd.h>
#include <boost/scope_exit.hpp>
#include <boost/interprocess/mapped_region.hpp>
#include <boost/interprocess/shared_memory_object.hpp>
#include <boost/interprocess/sync/interprocess_upgradable_mutex.hpp>
#include <boost/interprocess/sync/scoped_lock.hpp>
#include <boost/interprocess/sync/sharable_lock.hpp>
#include <boost/interprocess/sync/upgradable_lock.hpp>
// http://stackoverflow.com/questions/12439099/interprocess-reader-writer-lock-with-boost/
#define SHARED_MEMORY_NAME "SO12439099-MySharedMemory"
struct shared_data {
private:
typedef boost::interprocess::interprocess_upgradable_mutex upgradable_mutex_type;
mutable upgradable_mutex_type mutex;
volatile int counter;
public:
shared_data()
: counter(0)
{
}
int count() const {
boost::interprocess::sharable_lock<upgradable_mutex_type> lock(mutex);
return counter;
}
void set_counter(int counter) {
boost::interprocess::scoped_lock<upgradable_mutex_type> lock(mutex);
this->counter = counter;
}
};
int main(int argc, char *argv[])
{
using namespace boost::interprocess;
if (argc != 2) {
std::cerr << "Usage: " << argv[0] << " WHICH" << std::endl;
return 1;
}
const std::string which = argv[1];
if (which == "parent") {
shared_memory_object::remove(SHARED_MEMORY_NAME);
shared_memory_object shm(create_only, SHARED_MEMORY_NAME, read_write);
BOOST_SCOPE_EXIT(argc) {
shared_memory_object::remove(SHARED_MEMORY_NAME);
} BOOST_SCOPE_EXIT_END;
shm.truncate(sizeof (shared_data));
// Map the whole shared memory into this process.
mapped_region region(shm, read_write);
// Construct the shared_data.
new (region.get_address()) shared_data;
// Go to sleep for a minute.
sleep(60);
return 0;
} else if (which == "reader_child") {
shared_memory_object shm(open_only, SHARED_MEMORY_NAME, read_write);
mapped_region region(shm, read_write);
shared_data& d = *static_cast<shared_data *>(region.get_address());
for (int i = 0; i < 100000; ++i) {
std::cout << "reader_child: " << d.count() << std::endl;
}
} else if (which == "writer_child") {
shared_memory_object shm(open_only, SHARED_MEMORY_NAME, read_write);
mapped_region region(shm, read_write);
shared_data& d = *static_cast<shared_data *>(region.get_address());
for (int i = 0; i < 100000; ++i) {
d.set_counter(i);
std::cout << "writer_child: " << i << std::endl;
}
}
}
我在Mac上尝试使用以下脚本:
#!/usr/bin/env sh
./a.out reader_child &
./a.out reader_child &
./a.out writer_child &
./a.out reader_child &
./a.out reader_child &
(您必须先启动父级:./a.out parent
)
输出显示“reader_child”和“writer_child”行的交错(所有“reader_child”行在第一个“writer_child”行之后显示非零值),因此它似乎正在工作。