Question

这是我的数据：

+----------+---------------+------------+---------------------+
|  doctor  | received_date | patient_id | accession_daily_key |
+----------+---------------+------------+---------------------+
|  A       |  1/1/2011     |  ABC123    |                   1 |
|  A       |  1/20/2011    |  AAA123    |                   2 |
|  A       |  1/21/2011    |  AAA123    |                   3 |
|          |               |            |                   4 |
|  A       |  2/1/2011     |  ABC123    |                   5 |
|  A       |  2/9/2011     |  BBBYYY    |                   6 |
|          |               |            |                   7 |
|  B       |  1/2/2011     |  ABC123    |                   8 |
|  B       |  1/20/2011    |  AXA435    |                   9 |
|  B       |  1/19/2011    |  AAA123    |                  10 |
|          |               |            |                  11 |
|  B       |  2/1/2011     |  ABC123    |                  12 |
|  B       |  2/10/2011    |  BBBYYY    |                  13 |
+----------+---------------+------------+---------------------+

这是我想要的结果：

+--------+-------+--------------------+
| doctor | month | count new patients |
+--------+-------+--------------------+
| A      |     1 |                  1 |
| A      |     2 |                  1 |
| B      |     1 |                  2 |
| B      |     2 |                  0 |
+--------+-------+--------------------+

我想每月为新医生计算一名医生。

我获得的业务规则是：

患者只能与一名医生联系

患者所关联的医生是看见他的最后一位医生

这是我到目前为止所拥有的：

select patient_id,max(month(RECEIVED_DATE)) AS Mnth, max(year(RECEIVED_DATE)) AS Yr, ACCESSION_DAILY_KEY
    FROM [F_ACCESSION_DAILY] 
    where RECEIVED_MLIS_INFORMATION=1
    GROUP BY patient_id,ACCESSION_DAILY_KEY

此查询将为我提供包含患者所关联医生的行的primary key accession_daily_key 。

您能否指导我如何在每个月为每位医生提供每月最新的患者数量？

jcolebrand编辑：

CREATE TABLE F_ACCESSION_DAILY (
    doctor VARCHAR(10) NOT NULL
  , received_date DATETIME NOT NULL
  , patient_id VARCHAR(10) NOT NULL
  , accession_daily_key INT NOT NULL
)

INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('A','1/1/2011','ABC123','1')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('A','1/20/2011','AAA123','2')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('A','1/21/2011','AAA123','3')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('A','2/1/2011','ABC123','5')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('A','2/9/2011','BBBYYY','6')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('B','1/2/2011','ABC123','8')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('B','1/20/2011','AXA435','9')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('B','1/19/2011','AAA123','10')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('B','2/1/2011','ABC123','12')
INSERT INTO F_ACCESSION_DAILY (doctor,received_date,patient_id,accession_daily_key) VALUES ('B','2/10/2011','BBBYYY','13')

Answer 1

~~您可能需要使用子查询分两步执行此操作：~~

获取所有新患者就诊的清单：

选择医生，MIN（日期）AS首次访问，患者FROM访问GROUP BY患者;

按月分组

SELECT医生，COUNT（*），MONTH（firstvisit）AS月，YEAR（firstvisit）AS年份（...）GROUP BY医生，MONTH（firstvisit），YEAR（firstvisit）;

总而言之，以下内容应该有效：

SELECT doctor, COUNT(*) newPatients, MONTH(firstvisit) AS month, YEAR(firstvisit) AS year FROM (SELECT doctor, MIN(date) AS firstvisit ,patient FROM visits GROUP BY patient) GROUP BY doctor, MONTH(firstvisit), YEAR(firstvisit);

~~没有子查询可能会这样做，但我不确定它是否能正常工作。~~

好的，编辑更新：

您现在需要四个（？）步骤：

确定每位患者的最后一次就诊

SELECT患者，MAX（日期）lastvisit FROM访问GROUP BY患者;
确定每位专利的相关医生，作为上次就诊的医生：

选择医生，患者FROM访问v LEFT JOIN（...）lv ON v.patient = lv.patient WHERE v.date = lv.lastvisit;
与他们的最新医生确定第一次就诊

选择医生，患者，MIN（日期）firstvisit 来自访问v LEFT JOIN（...）dp ON v.doctor = dp.doctor WHERE v.patient = dp.patient GROUP BY患者;
和以前一样，每个医生每月第一次就诊：

SELECT医生，COUNT（*），MONTH（firstvisit）AS月，YEAR（firstvisit）AS年 FROM（...）GROUP by doctor，MONTH（firstvisit），YEAR（firstvisit）;

给予一个稍微可怕且有效的总数：

SELECT doctor, COUNT(*), MONTH(firstvisit) AS month, YEAR(firstvisit) AS year FROM ( SELECT doctor, patient, MIN(date) firstvisit FROM visits v LEFT JOIN ( SELECT doctor, patient FROM visits v LEFT JOIN ( SELECT patient, date lastvisit FROM visits GROUP BY patient) lv ON v.patient=lv.patient WHERE v.date=lv.lastvisit) dp ON v.doctor=dp.doctor WHERE v.patient=dp.patient GROUP BY patient) GROUP BY doctor, MONTH(firstvisit), YEAR(firstvisit);

我认为这可能至少会被压缩一点。

EDIT2：感谢jcolebrand，正在使用SQL：http://sqlfiddle.com/#!3/41beb/25

SELECT
       t.doctor
     , COUNT(t.doctor)
     , MONTH(t.firstvisit) AS MONTH
     , YEAR(t.firstvisit) AS YEAR
  FROM (
    SELECT
           v.doctor
         , v.patient_id
         , MIN(received_date) firstvisit
      FROM F_ACCESSION_DAILY v
 LEFT JOIN (
            SELECT
                   v.doctor
                 , v.patient_id
              FROM F_ACCESSION_DAILY v
         LEFT JOIN (
                    SELECT patient_id
                         , received_date lastvisit
                      FROM F_ACCESSION_DAILY
                  GROUP BY patient_id
                         , received_date
                  ) lv ON v.patient_id=lv.patient_id
             WHERE v.received_date=lv.lastvisit
          ) dp ON v.doctor = dp.doctor
    WHERE v.patient_id=dp.patient_id
    GROUP BY v.patient_id
           , v.doctor
  ) t
 GROUP BY
       t.doctor
     , MONTH(t.firstvisit)
     , YEAR(t.firstvisit);

Answer 2

请注意，这是他的第一次信息迭代，并且因为Zeb已经做了一个很好的工作并得到了进一步的答案，我将其留下来用于历史追踪。你可以随意忽略这个答案，但是对于迭代过程，这是一个很好的学习范例。

这似乎应该做你需要的，我想

SELECT
       MIN(received_date) AS FirstVisit
     , patient_id         AS PatientID
INTO #LookupTable
FROM F_ACCESSION_DAILY

SELECT 
       f.doctor           AS Doctor
     , COUNT(f.*)         AS CountNewPatients
     , MONTH(firstvisit)  AS Month
     , YEAR(firstvisit)   AS Year
FROM F_ACCESSION_DAILY f 
INNER JOIN #LookupTable l ON f.received_date = l.FirstVisit 
                         AND f.patient_id = l.PatientID
GROUP BY f.doctor
       , MONTH(firstvisit)
       , YEAR(firstvisit)

DROP TABLE #LookupTable

根据上次就诊日期与医生对患者记录进行分组和统计

2 个答案: