我是Node.js和Jade的新手，我尝试使用#{Date.now()}并且它给了我数字。如何以mm/dd/yy格式显示日期？
答案 0 :(得分：73)
首先，为您的快速应用程序本地人添加时刻
express = require('express');
...
app = express();
app.locals.moment = require('moment');
然后你可以在玉石模板中使用这样的时刻：
p #{moment(Date.now()).format('MM/DD/YYYY')}
默认情况下，时间为Date.now()，所以你也可以写：
p #{moment().format('MM/DD/YYYY')}
来源：
答案 1 :(得分：8)
或者您可以使用moment.js库来处理日期并根据您的需要对其进行格式化
答案 2 :(得分：6)
这是旧的，但我会做以下事情：
return (new Date()).toLocaleDateString()
返回日期'mm / dd / yyyy'格式，不需要额外的库。
答案 3 :(得分：4)
我实际上开始使用date-util，它是客户端和服务器端的两部分。
网址https://github.com/JerrySievert/node-date-utils
在浏览器中使用
<script type="text/javascript" src="date-utils.min.js"></script>
与Node.js一起使用
$ npm install date-utils
require('date-utils');
注意：由于Node.js如何处理REPL中的上下文，这在Node.js 0.6之前的REPL中不起作用。
静态方法
Date.today(); // today, 00:00:00
Date.yesterday(); // yesterday, 00:00:00
Date.tomorrow(); // tomorrow, 00:00:00
Date.validateDay(day, year, month); // true/false whether a date is valid
Date.validateYear(year); // true/false whether a year is valid
Date.validateMonth(month); // true/false whether a month is valid
Date.validateHour(hour); // true/false whether an hour is valid
Date.validateMinute(minute); // true/false whether a minute is valid
Date.validateSecond(second); // true/false whether a second is valid
Date.validateMillisecond(millisecond); // true/false whether a millisecond is valid
Date.compare(date1, date2); // -1 if date1 is smaller than date2, 0 if equal, 1 if date2 is smaller than date1
Date.equals(date1, date2); // true/false if date1 is equal to date2
Date.getDayNumberFromName(name); // su/sun/sunday - 0, mo/mon/monday - 1, etc
Date.getMonthNumberFromName(name); // jan/january - 0, feb/february - 1, etc
Date.isLeapYear(year); // true/false whether the year is a leap year
Date.getDaysInMonth(monthNumber); // number of days in the month
实例方法
d.clone(); // returns a new copy of date object set to the same time
d.getMonthAbbr(); // abreviated month name, Jan, Feb, etc
d.getMonthName(); // fill month name, January, February, etc
d.getUTCOffset(); // returns the UTC offset
d.getOrdinalNumber(); // day number of the year, 1-366 (leap year)
d.clearTime(); // sets time to 00:00:00
d.setTimeToNow(); // sets time to current time
d.toFormat(format); // returns date formatted with:
// YYYY - Four digit year
// MMMM - Full month name. ie January
// MMM - Short month name. ie Jan
// MM - Zero padded month ie 01
// M - Month ie 1
// DDDD - Full day or week name ie Tuesday
// DDD - Abbreviated day of the week ie Tue
// DD - Zero padded day ie 08
// D - Day ie 8
// HH24 - Hours in 24 notation ie 18
// HH - Padded Hours ie 06
// H - Hours ie 6
// MI - Padded Minutes
// SS - Padded Seconds
// PP - AM or PM
// P - am or pm
d.toYMD(separator); // returns YYYY-MM-DD by default, separator changes delimiter
d.between(date1, date2); // true/false if the date/time is between date1 and date2
d.compareTo(date); // -1 if date is smaller than this, 0 if equal, 1 if date is larger than this
d.equals(date); // true/false, true if dates are equal
d.isBefore(date); // true/false, true if this is before date passed
d.isAfter(date); // true/false, true if this is after date passed
d.getDaysBetween(date); // returns number of full days between this and passed
d.getHoursBetween(date); // returns number of hours days between this and passed
d.getMinutesBetween(date); // returns number of full minutes between this and passed
d.getSecondsBetween(date); // returns number of full seconds between this and passed
d.add({ milliseconds: 30,
minutes: 1,
hours: 4,
seconds: 30,
days: 2,
weeks: 1,
months: 3,
years: 2}); // adds time to existing time
d.addMilliseconds(number); // add milliseconds to existing time
d.addSeconds(number); // add seconds to existing time
d.addMinutes(number); // add minutes to existing time
d.addHours(number); // add hours to existing time
d.addDays(number); // add days to existing time
d.addWeeks(number); // add weeks to existing time
d.addMonths(number); // add months to existing time
d.addYears(number); // add years to existing time
答案 4 :(得分：1)
您需要使用Date对象上的方法来实现您所追求的目标。见https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Date
例如，下面的代码应该满足您的需求：
var dateNow = new Date();
var dd = dateNow.getDate();
var monthSingleDigit = dateNow.getMonth() + 1,
mm = monthSingleDigit < 10 ? '0' + monthSingleDigit : monthSingleDigit;
var yy = dateNow.getFullYear().toString().substr(2);
var formattedDate = mm + '/' + dd + '/' + yy;
因此，如果您使用带有express和node的jade，您可以执行以下操作：
res.render('jadeTemplateName', {
dateNow: function() {
var dateNow = new Date();
var dd = dateNow.getDate();
var monthSingleDigit = dateNow.getMonth() + 1,
mm = monthSingleDigit < 10 ? '0' + monthSingleDigit : monthSingleDigit;
var yy = dateNow.getFullYear().toString().substr(2);
return (mm + '/' + dd + '/' + yy);
}
})
并在您的玉石模板中说明您是否要将日期添加到范围：
span Today's date is #{dateNow()}
答案 5 :(得分：0)
将类.post-date添加到包含日期的标记
document.addEventListener('DOMContentLoaded', function() {
var list = document.getElementsByClassName('post-date');
// get the number of selected elements
// iterate over elements and output their HTML content
for (var i=0; i<list.length; i++){
//console.log(list[i].innerHTML);
var string=list[i].innerHTML;
var length = 15;
var trimmedString = string.substring(0, length);
list[i].innerHTML=trimmedString ;
}
})
答案 6 :(得分：0)
我找到了解决方案 1.使用 - 语法在哈巴狗中创建一个函数 2.当pug.js将变量绑定到pug模板时，将varible传递给函数
-function prettyDate(dateString){
-var date = new Date(dateString);
-var d = date.getDate();
-var monthNames = [ "Jan", "Feb", "Mar", "Apr", "May", "Jun","Jul", "Aug", "Sep", "Oct", "Nov", "Dec" ];
-var m = monthNames[date.getMonth()];
-var y = date.getFullYear();
-return d+' '+m+' '+y;
-}
3.span.post-date #{prettyDate(val.date)};