我正在尝试创建一个小的sinatra示例,该示例将打印一个月,日或年的日历视图,具体取决于URL。这样
localhost:4567 / calendar / 2012将打印年视图日历
localhost:4567 / calendar / 2012/9将打印一个月日历
localhost:4567 / calendar / 2012/9/15将打印日视图日历
我的工作原理如下:
require 'sinatra'
get '/calendar/:year/:month/:day/?' do
"printing daily calendar for #{params[:year]}/#{params[:month]}/#{params[:day]}"
end
get '/calendar/:year/:month/?' do
"printing monthly calendar for #{params[:year]}/#{params[:month]}"
end
get '/calendar/:year/?' do
"printing yearly calendar for #{params[:year]}"
end
我的问题是,我是否可以使用某种RegEx进一步优化这些路由,以便我可以说如果:月份部分介于1和12之间并且:day部分介于1和31之间,则仅计算url吗
答案 0 :(得分:7)
如果您使用的是ruby 1.9+,则可以使用这样的命名捕获:
get %r{/(?<year>\d{4})/(?<month>\d{2})/(?<day>\d{2})/?} do
"printing daily calendar for #{params[:year]}/#{params[:month]}/#{params[:day]}"
end
get %r{/(?<year>\d{4})/(?<month>\d{2})/?} do
"printing monthly calendar for #{params[:year]}/#{params[:month]}"
end
get %r{/(?<year>\d{4})/?} do
"printing monthly calendar for #{params[:year]}"
end
答案 1 :(得分:2)
是。您可以在sinatra路由条件中指定正则表达式。有关详细信息,请参阅sinatra readme。
get %r{/calendar/([\d]+)/(1[0-2]|0?[1-9])/([12][0-9]|3[0-1]|0?[1-9])$} do
"hello #{params[:captures]}"
end
get %r{/calendar/([\d]+)/(1[0-2]|0?[1-9])$} do
"hello #{params[:captures]}"
end
# host/2012/11 will print "hello [2012, 11]"
# params[:captures] will return an array containing what match the regular expressions