Question

我从Postgres中选择一个名称，一个动作和一个按名称ASC排序的计数，行动ASC如下：

SELECT u.firstname || ' ' || u.surname AS user,
    nt.name AS action,
    cn.count
FROM (
    SELECT actioned_by_id, note_type_id, COUNT(id) AS count
    FROM customer_notes
    WHERE actioned_date IS NOT NULL 
    GROUP BY actioned_by_id, note_type_id
) AS cn
LEFT JOIN note_type AS nt ON cn.note_type_id = nt.id
LEFT JOIN users as u on cn.actioned_by_id = u.id
WHERE cn.actioned_by_id IS NOT NULL 
ORDER BY user, action;

然而，结果显示它忽略了用户子句并且仅按动作排序。

"ADMIN USER" "CALL OUT"   1
"ADMIN USER" "EMAIL"      1
"ADMIN USER" "LETTER"     2
"AA AA"      "MEETING"    1
"ADMIN USER" "PHONECALL"  7
"AA AA"      "PHONECALL"  1

任何人都明白为什么？以及如何正确订购？

Answer 1

user是保留字 - 返回当前用户名

尝试

order by u.firstname || ' ' || u.surname, action

Answer 2

尝试使用列的位置

进行排序

SELECT u.firstname || ' ' || u.surname AS user,
    nt.name AS action,
    cn.count
FROM (
    SELECT actioned_by_id, note_type_id, COUNT(id) AS count
    FROM customer_notes
    WHERE actioned_date IS NOT NULL 
    GROUP BY actioned_by_id, note_type_id
) AS cn
LEFT JOIN note_type AS nt ON cn.note_type_id = nt.id
LEFT JOIN users as u on cn.actioned_by_id = u.id
WHERE cn.actioned_by_id IS NOT NULL 
ORDER BY 1, 2;

Answer 3

尝试此订单条款： -

ORDER BY u.firstname || ''|| u.surname，action;

我认为它忽略了USER列的顺序，因为它是派生列 - 您需要指定派生本身，而不是派生的名称。

Postgres没有正确排序两列

3 个答案: