Question

我在struts2 MVC中创建了一个项目。任何人都可以告诉我如何在不指向struts2.xml的情况下访问servlet？我知道我们可以通过动作调度程序通过struts2.xml访问，但我想知道是否有任何其他方法可以直接从jsp访问servlet？

的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
    <filter>
        <filter-name>struts2</filter-name>
        <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
    </filter>
    <filter-mapping>
        <filter-name>struts2</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>
    <servlet>
        <servlet-name>MyServlet</servlet-name>
        <servlet-class>com.myservlet.MyServlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>MyServlet</servlet-name>
        <url-pattern>/MyServlet</url-pattern>
    </servlet-mapping>
    <session-config>
        <session-timeout>
            30
        </session-timeout>
    </session-config>
    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>
</web-app>

struts.xml中

<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">

<struts>
    <!-- Configuration for the default package. -->
    <package name="default" extends="struts-default">

    </package>
</struts>

MyServlet.java

package com.myservlet;

import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.swing.JOptionPane;

public class MyServlet extends HttpServlet {
    protected void processRequest(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
        response.setContentType("text/html;charset=UTF-8");
        PrintWriter out = response.getWriter();
        try {
        } finally { 
            out.close();
        }
    } 
    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
        processRequest(request, response);

    } 

    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
        processRequest(request, response);
        PrintWriter out = response.getWriter();
        String name=request.getParameter("username");
        JOptionPane.showMessageDialog(null,"SEEE:"+name);
    }

    @Override
    public String getServletInfo() {
        return "Short description";
    }// </editor-fold>

}

的index.jsp

<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
   "http://www.w3.org/TR/html4/loose.dtd">

<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>JSP Page</title>
    </head>
    <body>
        <form action="MyServlet" method="post">
            USERNAME:<input type="text" name="username"/><br>
            <input type="submit" value="SHOW"/>
        </form>
    </body>
</html>

在上面的代码中为什么我无法访问getPost（）方法中textfield的值？在此先感谢...

Answer 1

我相信你知道如何调用servlet以及如何配置它们，所以我不会详细说明。

您可以创建servlet并根据您的用例调用它们，只需告诉Struts2过滤器您不希望Struts2处理某些特定的URL

在struts.xml添加：

<constant name="struts.action.excludePattern" value="/ServletToExcludeFromStruts*"/>

有关详细信息，请参阅webxml

无需通过struts2.xml即可访问servlet？

1 个答案: