Question

我在 C＃windows程序中遇到问题，即我无法使用2个数据库表和数据中的简单数据库。在这个项目中，我想打开Access数据库和创建新的Access数据库与另一个名称但具有相同的表和列和行并填充源源数据库中的数据。

我无法从源DB读取并插入新目标DataBase。下面的代码请帮我完成这个项目，非常感谢。

private void button3_Click(object sender, EventArgs e)
{
    OleDbConnection cn = new OleDbConnection();
    cn.ConnectionString = @"provider=Microsoft.ACE.OLEDB.12.0;" + @"data source=" + openFileDialog1.FileName;
    OleDbCommand cmd = new OleDbCommand();
    cn.Open();
    DataTable table = cn.GetSchema("Tables");

    int i = 0;
    foreach (System.Data.DataRow row in table.Rows)
    {
        if ((string)row["TABLE_TYPE"] == "TABLE")
        {
            comboBox1.Items.Add(row["TABLE_NAME"]);
            Tables[i] = row["TABLE_NAME"].ToString();
            listBox1.Items.Add(Tables[i]);
            i++;
            n++;
        }
    }
}
private void comboBox1_SelectedIndexChanged(object sender, EventArgs e)
{
    OleDbConnection conne = new OleDbConnection();
    conne.ConnectionString = @"provider=Microsoft.ACE.OLEDB.12.0;" + @"data source=" + openFileDialog1.FileName;
    conne.Open();
    OleDbCommand cmd = new OleDbCommand();
    cmd.Connection = conne;
    DataTable Dt = new DataTable();
    cmd.CommandText = "select * from " + comboBox1.Text;
    OleDbDataAdapter adapter = new OleDbDataAdapter();
    adapter.SelectCommand = cmd;
    adapter.Fill(Dt);
    dataGridView1.DataSource = Dt;
    dataGridView1.Visible = true;
    conne.Close();
}
private void button2_Click(object sender, EventArgs e)
{
    saveFileDialog1.Filter = "accdb|*.accdb";
    saveFileDialog1.Title = "Save Access DataBase File";
    saveFileDialog1.FileName = strFileName;
    saveFileDialog1.ShowDialog();
    System.IO.File.Copy(openFileDialog1.FileName, saveFileDialog1.FileName);

    ADOX.Catalog cat = new ADOX.Catalog();
    cat.Create("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + saveFileDialog1.FileName);
    Console.WriteLine("Database Created Successfully");
    OleDbConnection connsave = new OleDbConnection();
    connsave.ConnectionString = @"provider=Microsoft.ACE.OLEDB.12.0;" + @"data source=" + saveFileDialog1.FileName;
    connsave.Open();
    OleDbCommand cmdsave = new OleDbCommand();
    cmdsave.Connection = connsave;

    OleDbConnection connopen = new OleDbConnection();
    connopen.ConnectionString = @"provider=Microsoft.ACE.OLEDB.12.0;" + @"data source=" + openFileDialog1.FileName;
    connopen.Open();
    OleDbCommand cmdopen = new OleDbCommand();
    cmdopen.Connection = connopen;

    int i = 0;

    foreach (string strtablename in Tables)
    {
        if (i < n)
        {
            cmdsave.CommandText = "CREATE TABLE [" + Tables[i] + "]";
            cmdsave.ExecuteNonQuery();
            cmdsave.CommandText = "DELETE FROM [" + Tables[i] + "]";
            cmdsave.ExecuteNonQuery();
            cmdopen.CommandText = "SELECT * FROM [" + Tables[i] + "]";
            cmdopen.ExecuteNonQuery();
            cmdsave.CommandText = "INSErT INTO [" + Tables[i] + "]";
            cmdsave.ExecuteNonQuery();                       
            i++;
        }
    }
    connopen.Close();
    connsave.Close();
    textBox2.Text = saveFileDialog1.FileName.ToString();
    MessageBox.Show("DataBase Save Sucessfull in \"" + textBox2.Text + "\"");
}

Answer 1

您可以使用INSERT INTO子句执行IN语句：

INSERT INTO DestinationTable (DestinationField)
IN '' [;DATABASE= C:\Users\Rob\Documents\Northwind 2007.accdb]
SELECT SourceField FROM SourceTable

他们在这里详细介绍： http://blogs.office.com/b/microsoft-access/archive/2009/03/27/accessing-external-data-using-the-in-clause.aspx

创建新的DataBase＆amp;填写另一个DataBase

1 个答案: