在PHP中获取给定URL的Google +共享

时间:2012-09-12 15:37:09

标签: php google-plus google-plus-one

我想在PHP中获取google plus上的给定URL的份额数。我找到了这个功能:

function get_shares_google_plus($url) {
  $curl = curl_init();
  curl_setopt($curl, CURLOPT_URL, "https://clients6.google.com/rpc");
  curl_setopt($curl, CURLOPT_POST, 1);
  curl_setopt($curl, CURLOPT_POSTFIELDS, '[{"method":"pos.plusones.get","id":"p","params":{"nolog":true,"id":"' . $url . '","source":"widget","userId":"@viewer","groupId":"@self"},"jsonrpc":"2.0","key":"p","apiVersion":"v1"}]');
  curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-type: application/json'));
  $curl_results = curl_exec ($curl);
  curl_close ($curl);
  $json = json_decode($curl_results, true);
  print_r($json);
  return intval( $json[0]['result']['metadata']['globalCounts']['count'] );
}

但是,我总是收到同样的消息:Notice: Undefined index: result in ...

我制作print_r($json),我得到:Array ( [0] => Array ( [error] => Array ( [code] => 400 [message] => Invalid Value [data] => Array ( [0] => Array ( [domain] => global [reason] => invalid [message] => Invalid Value ) ) ) [id] => p )

有什么建议吗?

3 个答案:

答案 0 :(得分:8)

RPC API从未打算供公众使用,Google更改了身份验证以防止滥用。因此,您发布的代码不再起作用。但是,我找到了一个更简单的解决方案:

更新(2013年1月23日): Google于2012年12月封锁了此网址 - 因此此方法不再有效!
更新(15.05.2013):该方法再次有效!

<?php
/**
 * Get the numeric, total count of +1s from Google+ users for a given URL.
 * @author          Stephan Schmitz <eyecatchup@gmail.com>
 * @copyright       Copyright (c) 2013 Stephan Schmitz
 * @license         http://eyecatchup.mit-license.org/  MIT License
 * @link            <a href="https://gist.github.com/eyecatchup/8495140">Source</a>.
 * @param   $url    string  The URL to check the +1 count for.
 * @return  intval          The total count of +1s.
 */
function getGplusShares($url) {
    $url = sprintf('https://plusone.google.com/u/0/_/+1/fastbutton?url=%s', urlencode($url));
    preg_match_all('/{c: (.*?),/', file_get_contents($url), $match, PREG_SET_ORDER);
    return (1 === sizeof($match) && 2 === sizeof($match[0])) ? intval($match[0][1]) : 0;
}

更新(2014年1月18日):这是一个改进版本,它使用curl,一个备用主机并进行一些错误处理(最新版本可以在https://gist.github.com/eyecatchup/8495140找到)。

<?php
/**
 * GetPlusOnesByURL()
 *
 * Get the numeric, total count of +1s from Google+ users for a given URL.
 *
 * Example usage:
 * <code>
 *   $url = 'http://www.facebook.com/';
 *   printf("The URL '%s' received %s +1s from Google+ users.", $url, GetPlusOnesByURL($url));
 * </code>
 *
 * @author          Stephan Schmitz <eyecatchup@gmail.com>
 * @copyright       Copyright (c) 2014 Stephan Schmitz
 * @license         http://eyecatchup.mit-license.org/  MIT License
 * @link            <a href="https://gist.github.com/eyecatchup/8495140">Source</a>.
 * @link            <a href="http://stackoverflow.com/a/13385591/624466">Read more</a>.
 *
 * @param   $url    string  The URL to check the +1 count for.
 * @return  intval          The total count of +1s.
 */
function GetPlusOnesByURL($url) {
    !$url && die('No URL, no results. ;)');

    !filter_var($url, FILTER_VALIDATE_URL) &&
        die(sprintf('PHP said, "%s" is not a valid URL.', $url));

    foreach (array('apis', 'plusone') as $host) {
        $ch = curl_init(sprintf('https://%s.google.com/u/0/_/+1/fastbutton?url=%s',
                                      $host, urlencode($url)));
        curl_setopt_array($ch, array(
            CURLOPT_FOLLOWLOCATION => 1,
            CURLOPT_RETURNTRANSFER => 1,
            CURLOPT_SSL_VERIFYPEER => 0,
            CURLOPT_USERAGENT      => 'Mozilla/5.0 (Windows NT 6.1; WOW64) ' .
                                      'AppleWebKit/537.36 (KHTML, like Gecko) ' .
                                      'Chrome/32.0.1700.72 Safari/537.36' ));
        $response = curl_exec($ch);
        $curlinfo = curl_getinfo($ch);
        curl_close($ch);

        if (200 === $curlinfo['http_code'] && 0 < strlen($response)) { break 1; }
        $response = 0;
    }
    !$response && die("Requests to Google's server fail..?!");

    preg_match_all('/window\.__SSR\s\=\s\{c:\s(\d+?)\./', $response, $match, PREG_SET_ORDER);
    return (1 === sizeof($match) && 2 === sizeof($match[0])) ? intval($match[0][1]) : 0;
}

更新(02.11.2017): +1计数正式死亡!正如产品经理John Nack在this Google+ Post中宣布的那样,Google最近从其网络共享按钮中删除了共享计数(又名+1 Count)。 (他们声称此举的目的是让+1按钮和共享框加载更快。)

答案 1 :(得分:1)

此代码不起作用。此外,还没有提供此计数的公开API。

此代码使用为+1按钮提供动力的RPC API。此API不是官方支持的API,不应在Google+ plugins的内部实现之外使用。

答案 2 :(得分:0)

此处其他帖子中列出的cURL和API方式不再有效。

There is still at least 1 method,但它很难看,Google显然不支持它。您只需使用正则表达式从官方按钮的JavaScript源代码中删除变量:

function shinra_gplus_get_count( $url ) {
    $contents = file_get_contents( 
        'https://plusone.google.com/_/+1/fastbutton?url=' 
        . urlencode( $url ) 
    );

    preg_match( '/window\.__SSR = {c: ([\d]+)/', $contents, $matches );

    if( isset( $matches[0] ) ) 
        return (int) str_replace( 'window.__SSR = {c: ', '', $matches[0] );
    return 0;
}